Find the value of x.

Mathematics

1 answer:

Triss [41]3 years ago

6 0

Answer:

Step-by-step explanation:

The midsegment AC is half the sum of the parallel bases, that is

AC = $\frac{DF+EB}{2}$ , then

x = $\frac{13+9}{2}$ = $\frac{22}{2}$ = 11 → D

You might be interested in

There are 800 members in an astronomy club, and 320 of them are females. What percent of the members are males.

Liula [17]

ANSWER: 60% of the members are males

How?
-800 total
-320 females
800 - 320 = 480
480/800 = 0.6

Hope this Helps!

8 0

3 years ago

Read 2 more answers

Which of the following statements are true?

Eduardwww [97]

Answer:

B, C

Step-by-step explanation:

Consider all options:

A. The graph of the function $f(x)=\dfrac{1}{2}\sqrt[3]{x}$ is vertically shrunk by a factor $\frac{1}{2}$ the graph of the function $f(x)=\sqrt[3]{x},$ so the domain and the range of both functions are the same. This option is false.

B. The graph of the function $f(x)=\dfrac{1}{2}\sqrt[3]{x}$ is vertically shrunk by a factor $\frac{1}{2}$ the graph of the function $f(x)=\sqrt[3]{x},$ so the domain and the range of both functions are the same. This option is true.

C. The graph of the function $f(x)=\dfrac{1}{2}\sqrt[3]{(x-2)}$ is translated 2 units to the right and vertically shrunk by a factor $\frac{1}{2}$ the graph of the function $f(x)=\sqrt[3]{x},$ so their graphs are similar except the first graph is shifted right and shrunk vertically by a factor of $\frac{1}{2}.$ . This option is true.

D. The function $f(x)=\dfrac{1}{2}\sqrt{x}$ has the domain and the range all non-negative real values. The function $f(x)=\sqrt[3]{x}$ has the domain and the range all real values. So this option is false.