X/2 -15= -7 in verbal expression

Explain how you can use doubles when multiplying with 4 to find 4x8

STALIN [3.7K]

You can figure out what four times eight is by adding eight and eight(16) and doubling it (32)

8 0

4 years ago

Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)

babunello [35]

$\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k$

We want to find $f(x,y,z)$ such that $\nabla f=\vec F$ . This means

$\dfrac{\partial f}{\partial x}=x^2+y$

$\dfrac{\partial f}{\partial y}=y^2+x$

$\dfrac{\partial f}{\partial z}=ze^z$

Integrating both sides of the latter equation with respect to $z$ tells us

$f(x,y,z)=e^z(z-1)+g(x,y)$

and differentiating with respect to $x$ gives

$x^2+y=\dfrac{\partial g}{\partial x}$

Integrating both sides with respect to $x$ gives

$g(x,y)=\dfrac{x^3}3+xy+h(y)$

Then

$f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)$

and differentiating both sides with respect to $y$ gives

$y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C$

So the scalar potential function is

$\boxed{f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+\dfrac{y^3}3+C}$

By the fundamental theorem of calculus, the work done by $\vec F$ along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it $L$ ) in part (a) is

$\displaystyle\int_L\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(4,0,0)=\boxed{1+3e^4}$

and $\vec F$ does the same amount of work over both of the other paths.

In part (b), I don't know what is meant by "df/dt for F"...

In part (c), you're asked to find the work over the 2 parts (call them $L_1$ and $L_2$ ) of the given path. Using the fundamental theorem makes this trivial:

$\displaystyle\int_{L_1}\vec F\cdot\mathrm d\vec r=f(0,0,0)-f(4,0,0)=-\frac{64}3$

$\displaystyle\int_{L_2}\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(0,0,0)=\frac{67}3+3e^4$

8 0

3 years ago

2.48030477 rounded to the nearest hundred-thousandth is

ValentinkaMS [17]

<span>2.48030, its rounded tenths 2.5 hundreths 2.48 thousands 2.480 ten-thousands 2.4803 then </span>hundred-thousandth 2.48030

3 0

3 years ago

Please help in geometry

nekit [7.7K]

90 degrees

the diagonals intersect at right angles

4 0

4 years ago

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Use the discriminant to describe the roots of each equation. Then select the best description. 2m2 + 3 = m.

Tpy6a [65]

The roots of the equation , 2 $m^{2}$ +3=m, are non real roots.

<h3>Discriminants are what?</h3>

The quadratic formula's discriminant is represented by the square root symbol $b^{2}$ -4ac. If there are two solutions, one solution, or none at all, the discriminant informs us.

As of now, 2m²+3=m we need to find the kind of roots they have.

2m²+3=m

2m²-m+3=0

Here, we can derive the following values from the equation:

a = 2, b = -1, c = 3

An equation's discriminant is stated as:

D = b²-4ac

D = (-1)(-1) - 4(2)(3)

D = 1 - 24

D = -23

Discriminant can determine the kind of roots that the equation contains.

In this instance, the discriminant is below 0.

The equation's roots are complex conjugates when D < 0.

Hence the roots for the equation are non real roots.

To get more information about discriminant follow the link:

https://brainly.in/question/27214502

#SPJ4

4 0

1 year ago

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