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3 years ago

9

What are the zeros of the function

1 answer:

lilavasa [31]3 years ago

8 0

Answer:

(1,0)

Step-by-step explanation:

A.K.A the y and x intercepts you might need to do a little more math you get the y intercept tho

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This figure shows the procedure for constructing a

Yuri [45]

<span>In the question "This figure shows the procedure for constructing a" The correct answer is "bisector of an angle" (option C). To construct an angle bisector: Draw an arc that is centered at the vertex of the angle to intersect both sides of the angle. From the point of intersection of the previous arc and the both sides of the angle, draw two more arcs to intersect at a point. The radius for the two arcs must be equal. Then draw a straight line from the point of intersection of the later set of arcs and the vertex of the angle.</span>

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3 years ago

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State the domain, the range, and the intervals on which function is increasing, decreasing, or constant in interval notation

aleksandr82 [10.1K]

Answer:

Domain: $[-1,\infty)$

Range: $(-\infty, 3]$

Decreases over: $(-1,-\infty)$

Step-by-step explanation:

Given

$f(x) = -\sqrt{x + 1} + 3$ --- Missing from the question

Solving (a): The domain

To get the domain, the expression under the square root must not be negative.

In other words:

$x + 1 \ge 0$

Solve for x

$x + 1 -1\ge 0-1$

$x \ge -1$

Hence, the domain is:

$[-1,\infty)$

To get the range, we plot the values of the domain in the expression.

$x = -1$

$f(x) = -\sqrt{x + 1} + 3$

$f(-1) = -\sqrt{-1+1} +3$

$f(-1) = -\sqrt{0} +3$

$f(-1) = -0 +3$

$f(-1) = 3$

$x = \infty$

$f(\infty) = -\sqrt{\infty +1}+3$

$f(\infty) = -\sqrt{\infty}+3$

$f(\infty) = -\infty+3$

$f(\infty) = -\infty$

So, the range is: $(-\infty, 3]$

To get the interval where the function increases or not, we simply plot the graph of f(x).

See attachment for graph.

From the attachment, it will be observed that the graph of f(x) continuously decreases from x = -1, and it never increased.

This implies that, the graph decreases over the interval $(-1,-\infty)$

6 0

3 years ago

One solution of x^2 - 64 = 0 is 8. what is the other solution

wel

Answer:

- 8

Step-by-step explanation:

Given

x² - 64 = 0 ( add 64 to both sides )

x² = 64 ( take the square root of both sides )

x = ± $\sqrt{64}$ = ± 8

Solutions are x = 8 and x = - 8

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3 years ago

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Marrrta [24]

Answer:

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Step-by-step explanation:

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3 years ago

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harina [27]

5(3x-2)
5*3x - 5*2
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7 0

4 years ago

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