Question

Heres the pic i forgot to add. Again, pls help

Answer 1

Answer:

2$\sqrt{y} * \sqrt{3} x^2$

Explanation:

1) what is the square root of 4? 2!

2x$\sqrt{y} *sqrt{3x^2}$

2) $\sqrt{3x^{2} }$= $\sqrt{3x}$ = 2$\sqrt{3} xx \sqrt{y}$

3) Apply the exponent rule : xx=x^1+1

= 2$\sqrt{y}$ $\sqrt{3} x^2$

4) Add the numbers: 1+1=2

= 2$\sqrt{y} \sqrt{3} x^2$

Answer 2

Answer:

$2 \sqrt{3} x { }^{2} y$

Explanation:

this the anwers