Answer:
a. The possible dimensions of the total area are;
The width of the total area is (2·x + 8) inches
The length of the total area is (2·x + 10) inches
b. The dimensions of the photos are as follows;
The length of the photos are 10 inches
The width of the photos are 8 inches
Step-by-step explanation:
a. Given that the area, A = 4·x² + 36·x + 80
We get;
A = 4 × (x² + 9·x + 20) = 4 × (x + 4) × (x + 5) = (2·x + 8)·(2·x + 10)
Therefore, the possible dimensions of the total area (photo + mat) are;
The width of the total area (photo + mat) = (2·x + 8) in.
The length of the total area (photo + mat) = (2·x + 10) in.
b. The dimensions of the photos alone are shorter than the dimensions of the photo and mat combined by 2·x each
Therefore, we have the dimensions of the photos are as follows;
The length of the photo = (2·x + 10) in. - 2·x in. = 10 in.
The width of the photos = (2·x + 8) in. - 2·x in. = 8 in.
Answer:
1.05
Step-by-step explanation:
shop A: 2x3= 6
shop b: 5 for 1.10, 5 more for .55, so 1.65/10
1.65×3= 4.95
6-4.95= 1.05
By using a coordinate system I believe you can find the position of any objects on a flat surface.
If you have an eraser on your table and would like to know its position, you could make your own x and y axis and see in which quadrant your object is in.
your eraser could be 2 units in the x direction (horizontal) and 5 units in the y direction (vertical).
Now you can use this 'x and y' axis that you have drawn to locate any object.
If you want to be accurate, you should draw your axes with a meter ruler and choose your point of origin.
Hope I answered your question.
Answer:
0.011
Step-by-step explanation:
let's see so first
first you line the numbers on the right (DO NOT ALINE DECIMAL POINTS)
second, starting from on the right multiply each digit in the top number by each digit in the bottom number just as whole numbers .
after add the products
