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Rom4ik [11]
2 years ago
10

Suppose you deal three cards from a regular deck of 52 cards, What is the probability that they will all be jacks?

Mathematics
2 answers:
Klio2033 [76]2 years ago
8 0
Since there are 4 Jacks in the deck and 52 cards, the first time you draw a card the chances are 4/52 that you will draw a Jack.  Now that you have drawn a Jack, there are only 3 left in the deck so now the probability of drawing another Jack is 3/52.  The next Jack will be 2/52.  To get the probability that this will happen, we multiply the 3 fractions together...

4/52 * 3/52 * 2/52 = 24/140,608 = .00017 or .017%
Svetlanka [38]2 years ago
3 0

Answer:

0.00018

Step-by-step explanation:

The number of ways you can draw 3 cards from the deck of 52 cards is,

\dbinom{52}{3}=\dfrac{52!}{3!\ 49!}=\dfrac{52\times 51\times 50}{6}=22100

Out of 52, 4 cards are jacks. So the number of ways you can draw 3 jacks out of 4 is,

\dbinom{4}{3}=\dfrac{4!}{3!\ 1!}=\dfrac{24}{6}=4

So, the probability three cards from a regular deck of 52 cards will be,

\dfrac{4}{22100}=0.00018

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JulsSmile [24]
Set up a proportion.
24/x=9/15
24(15)=9x
360=9x
40=x

x=40

This is because if side one of the smaller triangle is 9 and side two of the smaller triangle is 15, and if side one of the larger triangle is 24 then side two of the larger triangle has to be 40 because they are proportional.

I hope this helps!
Best wishes :)
8 0
3 years ago
PLS HELP NEED THIS ASAP
lisabon 2012 [21]

Step-by-step explanation:

The equations that  could be used to determine the number of chicken wings and sliders in the combination meal is:

75w + 250s = 800

w = 2s

Where:

w = chicken wings

s = sliders

The two equations derived from the question are known as simultaneous equations. Both equations have to be solved together in order to determine the number of wings and sliders.

The total calories of wings = number of wings x calories of each wing

75 x w = 75w

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2 years ago
The diameter of a circle is 10 ft. Find its area in terms of pi
Alexxandr [17]
A = pi(r) ^2
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5 0
2 years ago
If the mean of 5 positive integers is 15, what is the maximum possible difference between the largest and the smallest of these
Vikki [24]

Answer:

if the 5 numbers are different, the maximum difference is 64

Step-by-step explanation:

We have 5 positive (different) integers, a, b, c, d and e (suppose that are ordered from least to largest, so a is the smallest and b is the largest.

The mean will be:

M = (a + b + c + d + e)/5 = 15.

Now, if we want to find the largest difference between a and e, then we must first select the first 4 numbers as the smallest numbers possible, this is:

a = 1, b = 2, c = 3 and d = 4

M = (1 + 2 + 3 + 4 + d)/5 = 15

M = (10 + d)/5 = 15

10 + d = 15*5 = 75

d = 75 - 10 = 65

then the difference between a and d is = 65 - 1 = 64.

Now, if we take any of the first 4 numbers a little bit bigger, then we will see that the value of d must be smaller, and the difference between d and a will be smaller.

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The mean age of 6 women in an office is 25 years old.
tresset_1 [31]

Answer:

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