All categories

3 years ago

When the hour hand moves from 3 pm to 6 pm, through how many degrees does it move?

Mathematics

1 answer:

taurus [48]3 years ago

6 0

I think it might be 90 degrees

You might be interested in

Um ok i need help pls give correct answers

vesna_86 [32]

-a) function 2, function 4
-b) function 4
-c) function 2

4 0

2 years ago

Read 2 more answers

Melissa has a collection of different colored hair bows. Some of the hair bows are big, and some of the hair bows are small. The

Brilliant_brown [7]

Answer:

7/55 or 12.727272727273%

Step-by-step explanation:

7/55 or 12.727272727273%

7 big and pink

so 7/?

?= amount of bows

and them up and you get 55

7/55

4 0

3 years ago

Tatami mats are used as a floor covering in Japan. one possible layout uses four identical rectangular mats and one square mat.

Basile [38]

So by definition, area is equal to the length (x) times the width (y). The area of the square mat is = x × y, or xy
If the area of the rectangular mat is twice that of the square mat, the area of the rectangular mat would have to be = 2 × x × y
This can be written as 2x × y, making the length of the rectangular mat twice that of the square mat's length, and the width the same as the square mat's width.

3 0

3 years ago

Read 2 more answers

Solve the inequality and identify solution. Please help. 5x-4>-4

Rudik [331]

Answer:

x > 0

Step-by-step explanation:

3 0

3 years ago

What is the solution of √x-5 = x-11

PIT_PIT [208]

Hey!

To solve x in this equation we must first add five to both sides to get $\sqrt{x}$ on its own.

Original Equation :
$\sqrt{x} - 5 = x - 11$

New Equation {Added 5 to Both Sides} :
$\sqrt{x} =x-6$

Now we must square both sides of the equation.

Old Equation :
$\sqrt{x} =x-6$

New Equation {Changed by Squaring Both Sides} :
$x= x^{2} -12x+36$

And now we must solve the new equation.

Step 1 - Switch sides
$x^{2} -12x+36=x$

Step 2 - Subtract x from both sides
$x^{2} -12x+36-x=x-x$

Step 3 - Simplify
$x^{2} -13x+36=0$

Now we need to solve the rest of the equation using the quadratic formula.

$\frac{-(-13)+ \sqrt{(-13) ^{2}-4*1*36 } }{2*1}$

${13+ \sqrt{(-13)^{2}-4*1*36 }=13+ \sqrt{25}$

$\frac{13+ \sqrt{25}}{2}$

$\sqrt{25}=5$

$\frac{13+5}{2}$

$\frac{18}{2}$

9

$\frac{-(-13)- \sqrt{(-13) ^{2} -4*1*36} }{2*1}$

4

So, this means that in the equation $\sqrt{x} -5=x-11$ , x = 9 and x = 4.

Hope this helps!

- Lindsey Frazier ♥

4 0

3 years ago