The smallest possible product of these four numbers is 59.0625
<h3>How to find the smallest possible product of these four numbers?</h3>
The equation is given as:
a + b + c + d = 12
The numbers are consecutive numbers.
So, we have:
a + a + 1 + a + 2 + a + 3 = 12
Evaluate the like terms
4a = 6
Divide by 4
a = 1.5
The smallest possible product of these four numbers is represented as:
Product = a * (a + 1) * (a + 2) * (a + 3)
This gives
Product = 1.5 * (1.5 + 1) * (1.5 + 2) * (1.5 + 3)
Evaluate
Product = 59.0625
Hence, the smallest possible product of these four numbers is 59.0625
Read more about consecutive numbers at:
brainly.com/question/10853762
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Answer:
7 inches
Step-by-step explanation:
area of square=l^2
49=l^2
=l
7=l
therefore the sides of a triangle is 7 inches.
The movement of the minute hand is circular.
Tangence speed is V=2Rπ/T= 2*7*3.14/3600 inches/sec=0.012211 inches/sec
The path (distance) that minute hand past is D=V*t = 0.012211 * 5 min= 0.012211 * 300sec=>
D=3.663≈3.66 inches
Good luck!!!
Hi.
To formally answer your question:
D. y = 0.75<em>x</em> + 11
We can prove this by substituting <em>x</em> with 1 (the initial measurement)
y = 0.75(1) + 11 = 11.75
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