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Artemon [7]
2 years ago
9

6. There are 450 students in the school. 60% are 6th graders. How mar

Mathematics
1 answer:
Rudiy272 years ago
3 0

Answer:

180

Step-by-step explanation:

40% are not 6th graders

10% of 450 if 45

there are four 10 percents in 40%, so 45 x 4 = 180

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Which of these numbers has the highest value? -22, 0.0099, 0, -1, (-1)
Oliga [24]
.0099 is the only positive number above zero and would have the highest value

5 0
3 years ago
Decompose 3/8 as the sum of unit fractions
bearhunter [10]
Unit fractions are fractions with a 1 as the numerator(number on top)
so 3/8 equals 1/8+1/8+1/8
8 0
3 years ago
Keegan is priting and selling his original design on t-shirts. He has concluded that for x shirts, in thousands sold his total p
Damm [24]

Complete question is;

Keegan is printing and selling his original design on t-shirts. He has concluded that for x shirts, in thousands sold his total profits will be p(x) = -x³ + 4x² + x dollars, in thousands will be earned. How many t-shirts (rounded to the nearest whole number) should he print in order to make maximum profits? What will his profits rounded to the nearest whole dollar be if he prints that number of shirts?

Answer:

Number of t-shirts to make maximum profit = 2790 shirts

Maximum profit = $12,209

Step-by-step explanation:

From the question, we are given that the profit function is;

p(x) = -x³ + 4x² + x

For the maximum value of the profit function,

(dp/dx) = 0 and (d²p/dx²) < 0

Since, p(x) = -x³ + 4x² + x

Then,

(dp/dx) = -3x² + 8x + 1

at maximum point (dp/dx) = 0, thus;

-3x² + 8x + 1 = 0

Solving this using quadratic formula, the roots are;

x = -0.12 or 2.79

Also, (d²p/dx²) = -6x + 8

Now, let's put the roots of x into -6x + 8 and check for maximum value conditon;

at x = -0.12

(d²p/dx²) = -6(0.12) + 8 = 7.28 > 0

At x = 2.79

(d²p/dx²) = -6(2.79) + 8 = -8.74 < 0

Maximum has to be d²p/dx² < 0

So, the one that meets the condition is -8.74 < 0 at x = 2.79

Thus, the maximum of the profit function exists when the number of shirts, x = 2.79 (in thousands) = 2790

Now, the maximum profits that corresponds to this number of t-shirts of 2.79(in thousands) is obtained by putting 2.79 for x in the profit function;

So,

p(2.79) = -(2.79)³ + 4(2.79²) + 2.79

p(x) = -21.7176 + 31.1364 + 2.79

p(x) = 12.2088 (in thousand dollars) ≈ $12,209

6 0
3 years ago
Mattie is making a collar for her dog. She needs to buy some chain,a clasp, and a name tag. She wants the chain to be 40 centime
Fantom [35]

Answer:the total cost of the collar is $5.11

Step-by-step explanation:

To make a collar for her dog, she needs to buy some chain,a clasp, and a name tag.

The length of the chain that she wants to buy is 40 centimeters.

1000 centimeters = 1 meter

40 centimeters = 40/1000 = 0.04 meters.

One meter of chain costs $9.75. Therefore, 0.04 meters of chain would cost

0.04 × 9.75 = $0.39

The clasp is $1.29 and the name tag is $3.43. Therefore, the total cost of the collar would be

0.39 + 1.29 + 3.43 = $5.11

8 0
3 years ago
Which ordered pairs are solutions to the inequality y−4x≥−5
Crank
You have to do substitution in both sides e) (-4,2)
3 0
3 years ago
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