All categories

3 years ago

What is the solution to 2x-8 <12

Mathematics

1 answer:

Nookie1986 [14]3 years ago

4 0

Step-by-step explanation:

2x-8<12

+8<+8

2x<20

$\frac{2x}{2} \frac{20}{2}$

x<10

You might be interested in

Please help me!!! 30 minutes left

Lesechka [4]

Option D:

$\frac{25 a^{9} b^{10} }{6 }$ is equivalent to the given expression.

Solution:

Given expression:

$$\frac{(5 a b)^{3}}{30 a^{-6} b^{-7}}$

To find which expression is equivalent to the given expression.

$$\frac{(5 a b)^{3}}{30 a^{-6} b^{-7}}$

Using exponent rule: $(ab)^m=a^mb^m$

$$=\frac{5^3 a^3 b^{3}}{30 a^{-6} b^{-7}}$

Using exponent rule: $\frac{1}{a^{m}}=a^{-m}, \quad \frac{1}{a^{-m}}=a^{m}$

$$=\frac{125 a^3 b^{3}a^{6} b^{7}}{30 }$

$$=\frac{125 a^3 a^{6} b^{3} b^{7}}{30 }$

Using exponent rule: $a^{m} \cdot a^{n}=a^{m+n}$

$$=\frac{125 a^{3+6} b^{3+7} }{30 }$

$$=\frac{125 a^{9} b^{10} }{30 }$

Divide both numerator and denominator by the common factor 5.

$$=\frac{25 a^{9} b^{10} }{6 }$

$$\frac{(5 a b)^{3}}{30 a^{-6} b^{-7}}=\frac{25 a^{9} b^{10} }{6 }$

Therefore, $\frac{25 a^{9} b^{10} }{6 }$ is equivalent to the given expression.

Hence Option D is the correct answer.

4 0

3 years ago

Using Cramer’s Rule, what is the value of y in the system of linear equations below?

Vadim26 [7]

for the system of equations

$a_1x+b_1y=c_1 \\a_2x+b_2y=c_2$

the three matrices needed to use Cramer's Rule are:

$D=\left[\begin{array}{cc}a_1&b_1\\a_2&b_2\end{array}\right] \\\\D_x=\left[\begin{array}{cc}c_1&b_1\\c_2&b_2\end{array}\right] \\\\D_y=\left[\begin{array}{cc}a_1&c_1\\a_2&c_2\end{array}\right]$ .

To use Cramer's Rule we have to calculate the three determinants listed below of the matrices listed below.

$D=\left[\begin{array}{cc}2&5\\-3&-2\end{array}\right] \\\\D_x=\left[\begin{array}{cc}-13&5\\3&-2\end{array}\right] \\\\D_y=\left[\begin{array}{cc}2&-13\\-3&3\end{array}\right]$ .