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Ivan
3 years ago
14

If a rectangular lot measures 120 ft. x 80 ft., and 10 foot set backs are required from each lot line, how much area is left? If

a kennel for 50 dogs requires 12,500 square feet, how many dogs can be accommodated in the small rectangle? There will be _________ square feet in the smaller lot. The number of dogs allowed is _________. (Use a whole number.)
Mathematics
1 answer:
tino4ka555 [31]3 years ago
7 0
The old rectangle will have a lot size of Area = 120 feet * 80 feet.
Old area = 9600 feet²
The new rectangle will have a lot size of Area =100 feet * 60feet
New area = 6000 feet².
Therefore smaller area is = 9600 - 6000 = 3600 feet²

Solving for the number of dogs, we have:
12, 500 square feet / 50 dogs = 250 ft²/dog 
6000 / 250 = 24 dogs 
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