Vertex form is
y=a(x-h)^2+k
vertex is (h,k)
axis of symmetry is x=4, therfor h=4
y=a(x-4)^2+k
we have some points
(3,-2) and (6,-26)
input and solve for a and k
(3,-2)
-2=a(3-4)^2+k
-2=a(-1)^2+k
-2=a(1)+k
-2=a+k
(6,-26)
-26=a(6-4)^2+k
-26=a(2)^2+k
-26=a(4)+k
-26=4a+k
we have
-2=a+k
-26=4a+k
multiply first equation by -1 and add to second
2=-a-k
<u>-26=4a+k +</u>
-24=3a+0k
-24=3a
divide both sides by 3
-8=a
-2=a+k
-2=-8+k
add 8 to both sides
6=k
the equation is
Answer:
Chart
Number of loaves Number of Bananas
1 2 1/2
2 5
4 10
Step-by-step explanation:
My friend helped me with this and since I saw no answer here I wanted to help YOU!!!!
So the first one was easy because it already said it in the number line.
The second one you simply multiply 2x 2 1/2
The third one you multiply 4x 2 1/2.
Hope it helps! Stay safe and dont go out during Quarantine!!!!!!!!!!
Umm im not sure maby like 1+1 or sum
Answer:
I think the ans is option 'a'
Final Answer:
Corresponding Angles Theorum; ∠AGF and ∠EHD are congruent
In the standard form of quadratic

the discriminant is

In your quadratic, a = 1, b = -9 and c = -10
Now you need to plug these values into the expression for the discriminant.