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jonny [76]
3 years ago
6

Which of the following is a point-slope equation of a line that passes through

Mathematics
1 answer:
34kurt3 years ago
8 0

Answer:

A

Step-by-step explanation:

m = Y2 - Y1/ X2 - X1

m= -7 - 5/ 4 - 10

m = -12/ -6

m = 2

y - y1 = m ( x - x1)

y - 5 = 2 (x - 10)

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Express 10500 in term if it's prime factor
Shkiper50 [21]
2 |  10500
2 !    5250
3 |     2625
5 |       875
5 |       175
5 |         35
             7
The prime factors are  2*2*3*5*5*5*7 or 2^2*3*5^3*7

3 0
3 years ago
What’s 3/4 x 22/7 x 2
Zolol [24]

Answer:

4\frac{5}{7}

Step-by-step explanation:

we just multiply numerator by numerator and denominator by denominator

3/4x22/7

66/28x2/1

132/28

4 20/28

4 5/7

Hopes this helps,please mark brainliest

3 0
10 months ago
Read 2 more answers
A bank loaned out $8200, part of it at a rate of 7.9% per year and the rest of it at a rate of 7.4% per year. The total amount o
Lady bird [3.3K]

The amount that the bank loaned out at 7.9% is $1,574.00

How do represent the amounts lent at different rates?

On the assumption that x amount was loaned at 7.9% and that the remaining amount, (8,200-x) was loan out at 7.4%, we can determine the interest charged on each loan as the loan multiplied by the interest rate

interest on 7.9% loan=7.9%*x=0.079x

interest on 7.4% loan=7.4%*(8200-x)

interest on 7.4% loan=606.80-0.074x

total interest=0.079x+606.80-0.074x

total interest=0.005x+606.80

total interest on loans=614.67

614.67=0.005x+606.80

614.67-606.80=0.005x

7.87=0.005x

x=7.87/0.005

x=amount loaned at 7.9%=$1,574.00

y=$8200-$1574

y=$6,626.00

Find out more about bank loan interest rate on:brainly.com/question/20796174

#SPJ1

3 0
1 year ago
Someone please help or i’ll be failing geometry this year
Vlad [161]

Step-by-step explanation:

I don't know what constructions you were taught.

a "similar" triangle is a triangle with exactly the same angles as the other triangle, but the lengths of all sides are stretched or shortened by the same scaling factor f.

by saying 1:2 she means the second triangle should have sides with twice the lengths of the first triangle (f=2).

and the extra challenge - same basic thing. she allows you to pick one of the two triangles as reference. and then you need to draw a third triangle (again with the same angles) with the side lengths extended by the scaling factor f of 4/3.

I would draw the triangles right on top of each other with the same starting corner (let's call it A) for all 3.

we would get the triangles ABC, AMN and AXY.

the points B and C would be then halfway on AM and AN.

and M and N would then a bit before X and Y on AX and AY.

the beauty is, you only need to construct 2 sides of every new triangle down to the new endpoints. the third side is automatically scaled correctly, and you only need to connect these new endpoints.

let's assume you draw a triangle (just very simple) ABC with all side lengths being 3. so, AB=3, AC=3, BC=3.

now you draw AMN by extending AB and AC to a side length of 6 (f=2) creating M and N, and you connect M and N.

and then you can create the third triangle AXY by extending AM and AN by a factor of 4/3 to side lengths of 8 (4/3 × 6 = 8) creating new end points X and Y. and you connect X and Y.

and that is it. all 3 triangles are similar (the same angles), and all sides of a triangle have the same length ratio to the sides of the other triangle(s).

4 0
2 years ago
7,14/5, 8/25 find the 7th term
tiny-mole [99]
I believe that would be 7
4 0
3 years ago
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