Ask question

Ask question

All categories

2 years ago

10

Please help asap!!!!!!

1 answer:

RSB [31]2 years ago

5 0

Answer:

z = 66

Step-by-step explanation:

QT is a midsegment. Thus, applying the midsegment theorem:

RS = 2(QT)

QT = z - 33,

RS = z

Plug in the values into the equation

z = 2(z - 33)

z = 2z - 66

Subtract 2z from each side

z - 2z = -66

-z = -66

Divide both sides by -1

z = 66

You might be interested in

the function f(x)=2•5x can be used to represent the curve through the points (1,10) (2,50) and (3,250). What is the multiplicati

Annette [7]

The answer would be 5

8 0

3 years ago

Read 2 more answers

15. Sense or Nonsense

ch4aika [34]

Says shouldn’t Say 18 inches because that is 1 ft 6 inches

3 0

2 years ago

Lori wants to determine the average amount of time that students at her school spend on a computer each day there are 350 studen

Bezzdna [24]

Answer:

2 students from each 15 classrooms

Step-by-step explanation:

"The number of boys and girls is approximately equal" is probably the most random sample, that is if the whole topic of the publication is Lorrie and her experimenting endeavors. If that is not the subject, then "Lorrie wants to determine the average amount of time that students at her school spend on the computer each day" is the most strange and random

3 0

3 years ago

The amount of time required for an oil and filter change on an automobile is normally distributed with a mean of 45 minutes and

Firdavs [7]

Answer:

1a

$P(39 < X < 48 ) = 0.8767$

1b

95% of all sample means will fall between $40.1 < \mu < 49.9$

1c

$\= x = 41. 795$

2

$n = 25$

Step-by-step explanation:

From the question we are told that

The mean is $n = 45$

The population standard deviation is $\sigma = 10$

The sample size is n = 16

Generally the standard error of the mean is mathematically represented as

$\sigma_{x} = \frac{ \sigma}{\sqrt{n} }$

=> $\sigma_{x} = \frac{ 10 }{\sqrt{16 } }$

=> $\sigma_{x} = 2.5$

Generally the probability that the sample mean will be between 39 and 48 minutes is

$P(39 < X < 48 ) = P( \frac{ 39 - 45}{ 2.5} < \frac{X - \mu }{\sigma } < \frac{ 48 - 45}{ 2.5} )$

=> $P(39 < X < 48 ) = P(-2.4 < Z< 1.2 )$

=> $P(39 < X < 48 ) = P( Z< 1.2 ) - P(Z < -2.4)$

From the z table the area under the normal curve to the left corresponding to 1.2 and -2.4 is

=> $P( Z< 1.2 ) = 0.88493$

and

$P( Z< - 2.4 ) = 0.0081975$

So

$P(39 < X < 48 ) = 0.88493 -0.0081975$

=> $P(39 < X < 48 ) = 0.8767$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E = 1.96 * 2.5$

=> $E =4.9$

Generally the 95% of all sample means will fall between

$\mu -E < and \mu +E$

=> $45 -4.9\ and \ 45 + 4.9$

Generally the value which 90% of sample means is greater than is mathematically represented

$P( \= X > \= x ) = 0.90$

=> $P( \= X > \= x ) = P( \frac{\= X - \mu }{ \sigma_x} > \frac{\= x -45 }{ 2.5} ) = 0.90$

=> $P( \= X > \= x ) = P( Z > z ) = 0.90$

Generally from the z-table the critical value of 0.90 is

$z = -1.282$

$\frac{\= x -45 }{ 2.5} = -1.282$

=> $\= x = 41. 795$

Considering question 2

Generally we are told that the standard deviation of the mean to be one fifth of the population standard deviation, this is mathematically represented as

$s = \frac{1}{5} \sigma$

Generally the standard deviation of the sample mean is mathematically represented as

$s = \frac{\sigma }{ \sqrt{n} }$

=> $\frac{1}{5} \sigma = \frac{\sigma }{ \sqrt{n} }$

=> $n = 5^2$

=> $n = 25$

5 0

2 years ago

How do you solve 3×(9+2-8÷16)

jek_recluse [69]

Remember order of operations (PEMDAS):

3•(11-1/2)
3•10.5
31.5

6 0

3 years ago