Answer:
3 ≤ y
Step-by-step explanation:
-4(y-6) ≤ (-9+y)(-2)
Distribute
-4y +24 ≤ 18 -2y
Add 4y to each side
-4y+4y +24 ≤ 18 -2y+4y
24≤ 18 +2y
Subtract 18 from each side
24-18≤ 18-18 +2y
6 ≤ 2y
Divide by 2
6/2≤ 2y/2
3 ≤ y
Answer:
hey hey hey hey hey hey
Step-by-step explanation:
Answer:
The required equation in standard form is 
Step-by-step explanation:
The equation of a circle with center (h,k) an radius, r units is given by the formula;
The given circle has center (-2,0) and radius squared can be calculated from the given area, which is 
We substitute these values into the formula to obtain;
We simplify to get;
To find the perimeter of the triangle, you must find the values of all sides of the triangle. That would be JL, LK and JK.
JL = JA + AL = 8 + 13 = 21
LK = LC + CK, LC is unknown. However, from the diagram, LK is tangent to the circle at point C, which is situated at the center of LK. This means that LC = CK. With that, we can find LK.
LK = 11 + 11 = 22
Lastly, we find JK. Notice that JK is tangent to the circle at point B and ends in point K. Similarly, JL is tangent to the circle at point A and ends at point L. Point A and B lies on the same level on the x-axis. Same is true with L and K. Therefore, they must have the same length. So, JL = JK = 21
Finally, we sum all sides to obtain the parameter:
P = JL + JK + LK = 21 + 21 + 22 = 64
Thus, the perimeter of triangle JKL is 64 units.
