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SpyIntel [72]
3 years ago
6

$9500 is invested, part of it at 11% and part of it at 8%. For a certain year, the total yield is $937.00. How much was invested

at each rate
Mathematics
1 answer:
netineya [11]3 years ago
8 0

Answer:

5900 at 11%

3600 at 8%

Step-by-step explanation:

x= invested at 11%

y= invested at 8%

x+y=9500

.11x+.08y=937

Mulitply the first equation by .11

.11x+.11y= 1045

Subtract this and the second equation

(.11x+.11y)-(.11x+.08y)=1045-937

.03y=108

y=3600

SOlve for x

x+3600=9500

x=5900

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\huge{ \fbox{ \sf{13 \: units}}}

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\star{ \sf{ \: Let \: the \: points \: be \: a \: and \: b}}

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\underline{ \sf{Finding \: the \: distance \: between \: the \: given \: points}} :

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\mapsto{ \sf{ \sqrt{144 + 25}}}

\mapsto{ \sf{ \sqrt{169} }}

\mapsto{ \sf{ \sqrt{ {(13)}^{2} } }}

\mapsto{ \sf{ 13 \: units}}

Hope I helped!

Best regards! :D

~\text{TheAnimeGirl}

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