$9500 is invested, part of it at 11% and part of it at 8%. For a certain year, the total yield is $937.00. How much was invested

Question

3 years ago

6

at each rate

1 answer:

netineya [11] · Answer 1 · 2022-05-07T09:43:57+03:00

8 0

Answer:

5900 at 11%

3600 at 8%

Step-by-step explanation:

x= invested at 11%

y= invested at 8%

x+y=9500

.11x+.08y=937

Mulitply the first equation by .11

.11x+.11y= 1045

Subtract this and the second equation

(.11x+.11y)-(.11x+.08y)=1045-937

.03y=108

y=3600

SOlve for x

x+3600=9500

x=5900