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hjlf
3 years ago
8

HELP PLEASE !!!!!!!!!!!!!

Mathematics
1 answer:
kvasek [131]3 years ago
8 0

Answer:

I believe it is y=147

Step-by-step explanation:

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if 368 teenagers in a population of 4,310 report that they have smoked at least one cigarette during the past year, to one decim
allochka39001 [22]
Divide the amount of teenagers that smoked by the total population:

368 \div 4310 = 0.0853

Multiply this decimal by 100 to convert into a percentage:

0.0853 \times 100 = 8.53

To round to the nearest decimal place, look at the hundredths value:

8.53
3 > 5
8.53 -> 8.5

8.5% of teenagers reported that they smoked at least one cigarette.
4 0
3 years ago
Will Mark Brainliest!!!!!!
astraxan [27]
You want to find the value of x for which the area under the curve to the left of x is 0.6. One way to do that is to create the cumulative distribution function (CDF) for the given PDF, then see where it is equal to 0.6.

Doing that, we find a = 5.

5 0
3 years ago
In Maria's physics class, she had to solve the equation 5=12at2+ut+x for u.
olasank [31]

Answer:

u= 5/t-12at-x/t

Step-by-step explanation:

I dont know what youre asking but that is the solved equation

7 0
3 years ago
Help with five plz!!!!!
frutty [35]

Answer:

No there cannot be the same number of stickers on each page.

Step-by-step explanation:

If you want to find out how many stickers need to be in every page to be even you would add all the stickers up. 6+6+9+10+11= 42. Take the 42 and divide it by 5 to see how many stickers would go in each page. This will give you 8.4. However since this number is a decimal it can't be split evenly in whole stickers for each page. Meaning that it wouldn't be possible for each page to have a evenly distributed number of stickers per each page.

5 0
3 years ago
Readings on a thermometer are normally distributed with a mean of 0C° and a standard deviation of 1.00. What is the probability
hichkok12 [17]

Given mean = 0 C and standard deviation = 1.00

To find probability that a random selected thermometer read less than 0.53, we need to find z-value corresponding to 0.53 first.

z= \frac{x-mean}{standard deviation}  = \frac{0.53-0}{1.00} = 0.53

So, P(x<0.53) = P(z<0.53) = 0.701944

Similarly P(x>-1.11)=P(z>-1.11) = 1-P(z<-1.11) = 0.8665

For finding probability for in between values, we have to subtract smaller one from larger one.

P(1.00<x<2.25) = P(1.00<z<2.25) = P(z<2.25)- P(z<1.00) = 0.9878 - 0.8413 = 0.1465

P(x>1.71) = P(z>1.71) = 1-P(z<1.71) = 1-0.9564 = 0.0436

P(x<-0.23 or x>0.23) = P(z<-0.23 or z>0.23)  =P(z<-0.23)+P(z>0.23) = 0.409+0.409 = 0.918

4 0
3 years ago
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