Answer:
Range [-2,2]
Cosine value varies from -1 to 1, hence -2cos 3x can vary from +2 to -2. The range of the given function , in interval notation, would thus be [-2,2]. In set builder notation it can be expressed as
{y∈R∣−2≤y≤2 }
It most likely might be wrong though so sorry for that.
Answer:
Y-Intercept would be 2, Slope would be 1
Step-by-step explanation:
The answer is x²-8x+13=0
Here is how:
[x-(4+√3)][x-(4-√3)]=0
expand and simplify:
x² -(4-√3)x - (4+√3) +(4+√3)(4-√3)=0
x²-8x+13=0
what in the hell grade are u in
(125^2x)(5x) = 25^3
(15625x)(5x)=15625
<span>78125x=15625
</span>x=5
Hope I helped ;D
