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2 years ago

Need help asap pls and ty.

Mathematics

2 answers:

Anastasy [175]2 years ago

8 0

Answer:

Step-by-step explanation:

Schach [20]2 years ago

3 0

I’m pretty sure the answer is D!

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If 2^x=5 what is 2^3^x - 4

vivado [14]

I believe the answer is 26

6 0

3 years ago

Read 2 more answers

BRO PLS I HAVE TO PASS THIS (click for question) 20 POINTS!

Masja [62]

Answer:

D, E.

Step-by-step explanation:

Simplify the expression inside the parentheses:

$3(23 + 18) < 6a$

$3(41) < 6a$

Multiply:

$123 < 6a$

Substitute each value provided for a:

Opt A. 123 < 6(18) = 123 < 108. Incorrect option.

Opt B. 123 < 6(19) = 123 < 114. Incorrect option.

Opt C. 123 < 6(20) = 123 < 120. Incorrect option.

Opt D. 123 < 6(22) = 123 < 132. Correct option.

Opt E. 123 < 6(24) = 123 < 144. Correct option.

3 0

2 years ago

A/20 + 14/15 = 9/15 Can i get some help?

KiRa [710]

Method 1:

$\dfrac{a}{20}+\dfrac{14}{15}=\dfrac{9}{15}\ \ \ \ |multiply\ both\ sides\ by\ 60\\\\60\cdot\dfrac{a}{20}+60\cdot\dfrac{14}{15}=60\cdot\dfrac{9}{15}\\\\3a+4\cdot14=4\cdot9\\\\3a+56=36\ \ \ \ |subtract\ 56\ from\ both\ sides\\\\3a=-20\ \ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{a=-\frac{20}{3}\to a=-6\frac{2}{3}}$

Method 2.

$\dfrac{a}{20}+\dfrac{14}{15}=\dfrac{9}{15}\ \ \ \ |subtract\ \dfrac{14}{15}\ form\ both\ sides\\\\\dfrac{a}{20}=-\dfrac{5}{15}\\\\\dfrac{a}{20}=-\dfrac{1}{3}\ \ \ \ |multiply\ both\ sides\ by\ 20\\\\\boxed{a=-\dfrac{20}{3}\to a=-6\frac{2}{3}}$

3 0

3 years ago

Assume a warehouse operates 24 hours a day. Truck arrivals follow Poisson distribution with a mean rate of 36 per day and servic

kirill [66]

The expected waiting time in system for typical truck is 2 hours.

Step-by-step explanation:

Data Given are as follows.

Truck arrival rate is given by, α = 36 / day

Truck operation departure rate is given, β= 48 / day

A constructed queuing model is such that so that queue lengths and waiting time can be predicted.

In queuing theory, we have to achieve economic balance between number of customers arriving into system and that of leaving the system whether referring to people or things, in correlating such variables as how customers arrive, how service meets their requirements, average service time and extent of variations, and idle time.

This problem is solved by using concept of Single Channel Arrival with exponential service infinite populate model.

Waiting time in system is given by,

$w_{s} = \frac{1}{\alpha - \beta }$