Deshaun exercises no less than 40 minutes per day.

A hypothesis regarding the weight of newborn infants at a community hospital is that the mean is 6.6 pounds. A sample of seven i

Elenna [48]

Answer:

The alternate hypothesis is that newborn infants has a mean weight of 7.56 pounds.

Step-by-step explanation:

Let's find an alternate hypothesis by using the formula:

mean=(sum of all data)/(number of data points) so:

sum of all data=9.0+7.3+6.0+8.8+6.8+8.4+6.6=52.9 and:

number of data points=7 so:

mean=52.9/7=7.56 pounds

The alternate hypothesis is that newborn infants has a mean weight of 7.56 pounds.

4 0

2 years ago

The cuboid has volume 288cm^3 (a) the cuboid has a length 12 cm and a width 5cm Calculate the height of the cuboid (b) 1cm^3 of

klemol [59]

Answer:

height= 4.8cm

Step-by-step explanation:

volume= length×width× height given the volume and length and width, 288=12×5×h

288=60h

divide both sides by 60

h=4.8cm

7 0

3 years ago

Read 2 more answers

10 normal six sided dice are thrown.Find the probability of obtaining at least 8 failuresif a success is 5 or 6.

erastova [34]

Answer:

0.2992 = 29.92% probability of obtaining at least 8 failures.

Step-by-step explanation:

For each dice, there are only two possible outcomes. Either a failure is obtained, or a success is obtained. Trials are independent, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A success is 5 or 6.

A dice has 6 sides, numbered 1 to 6. Since a success is 5 or 6, the other 4 numbers are failures, and the probability of failure is:

$p = \frac{4}{6} = 0.6667$

10 normal six sided dice are thrown.

This means that $n = 10$

Find the probability of obtaining at least 8 failures.

This is:

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)$

So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{10,8}.(0.6667)^{8}.(0.3333)^{2} = 0.1951$

$P(X = 9) = C_{10,9}.(0.6667)^{9}.(0.3333)^{1} = 0.0867$

$P(X = 10) = C_{10,10}.(0.6667)^{10}.(0.3333)^{0} = 0.0174$

Then

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1951 + 0.0867 + 0.0174 = 0.2992$

0.2992 = 29.92% probability of obtaining at least 8 failures.

8 0

3 years ago

Please help this is due after 30 minutes!

Tanzania [10]

Step-by-step explanation:

I entered it in and it was .9993319736

6 0

3 years ago

Read 2 more answers

Ox=20

nexus9112 [7]

No, it is not possible for Eric to have spent 35 minutes playing basketball if he plays for a total of exactly 95

<h3>How to form a linear equation</h3>

Let the time taken to play basketball be "x"

Let the time taken to play volleyball be "y"

According to the information given, Eric plays basketball and volleyball for a total of 95 minutes every day, then;

x + y = 95

If he plays basketball for 25 minutes long, then;

x = 25

The pair of linear equations that represents the statement are:

x + y = 95
x = 25

The time it takes Eric to play volleyball every day is expressed as:

y = 95 - x

y = 95 - 25

y = 70 minutes

No, it is not possible for Eric to have spent 35 minutes playing basketball if he plays for a total of exactly 95

Learn more on linear equations here: brainly.com/question/14323743

3 0

2 years ago