The slope is 2-2/6-6 which is zero . So the slope is no slope
Answer:
w = 0.215
Step-by-step explanation:
(8.25 + 1) / 4w = 10.75
9.25/4w = 10.75
9.25/4w(4w) = 10.75(4w)
9.25 = 43w
9.25/43 = w
w = 0.215
Answer:
y
=
4
(
1
2
)
x
Explanation:
An exponential function is in the general form
y
=
a
(
b
)
x
We know the points
(
−
1
,
8
)
and
(
1
,
2
)
, so the following are true:
8
=
a
(
b
−
1
)
=
a
b
2
=
a
(
b
1
)
=
a
b
Multiply both sides of the first equation by
b
to find that
8
b
=
a
Plug this into the second equation and solve for
b
:
2
=
(
8
b
)
b
2
=
8
b
2
b
2
=
1
4
b
=
±
1
2
Two equations seem to be possible here. Plug both values of
b
into the either equation to find
a
. I'll use the second equation for simpler algebra.
If
b
=
1
2
:
2
=
a
(
1
2
)
a
=
4
Giving us the equation:
y
=
4
(
1
2
)
x
If
b
=
−
1
2
:
2
=
a
(
−
1
2
)
a
=
−
4
Giving us the equation:
y
=
−
4
(
−
1
2
)
x
However! In an exponential function,
b
>
0
, otherwise many issues arise when trying to graph the function.
The only valid function is
y
=
4
(
1
2
)
x
Answer:
I think it's 2x/4 (1x/2 if simplified). if it's multiple choice that's what I'd go with and if that answer is wrong then sorry
Step-by-step explanation:
x•2 is 2x because you don't know the value x and you still have to divide by four. when simplified, 2/4 is 1/2 so it'd be 1x/2
One way would be to find the distance from the point to the center of the circle and compare it to the radius
for
![(x-h)^2+(y-k)^2=r^2](https://tex.z-dn.net/?f=%28x-h%29%5E2%2B%28y-k%29%5E2%3Dr%5E2)
the center is (h,k) and the radius is r
and the distance formula is
distance between
![(x_1,y_1)](https://tex.z-dn.net/?f=%28x_1%2Cy_1%29)
and
![(x_2,y_2)](https://tex.z-dn.net/?f=%28x_2%2Cy_2%29)
is
![D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B%28x_1-x_2%29%5E2%2B%28y_1-y_2%29%5E2%7D)
r=radius
D=distance form (8,4) to center
if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle
so
![(x+2)^2+(y-3)^2=18](https://tex.z-dn.net/?f=%28x%2B2%29%5E2%2B%28y-3%29%5E2%3D18)
![(x-(-2))^2+(y-3)^2=(\sqrt{18})^2](https://tex.z-dn.net/?f=%28x-%28-2%29%29%5E2%2B%28y-3%29%5E2%3D%28%5Csqrt%7B18%7D%29%5E2)
![(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2](https://tex.z-dn.net/?f=%28x-%28-2%29%29%5E2%2B%28y-3%29%5E2%3D%283%5Csqrt%7B2%7D%29%5E2)
the radius is
![3\sqrt{2}](https://tex.z-dn.net/?f=3%5Csqrt%7B2%7D)
center is (-2,3)
find distance between (8,4) and (-2,3)
![D=\sqrt{(8-(-2))^2+(4-3)^2}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B%288-%28-2%29%29%5E2%2B%284-3%29%5E2%7D)
![D=\sqrt{(8+2)^2+(1)^2}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B%288%2B2%29%5E2%2B%281%29%5E2%7D)
![D=\sqrt{10^2+1}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B10%5E2%2B1%7D)
![D=\sqrt{100+1}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B100%2B1%7D)
![D=\sqrt{101}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B101%7D)
![r=3\sqrt{2}](https://tex.z-dn.net/?f=r%3D3%5Csqrt%7B2%7D)
≈4.2
![D=\sqrt{101}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B101%7D)
≈10.04
do r<D
(8,4) is outside the circle