The answer is -3. it would have a negative charge to gain
<span>1 mole of benzene (78g) requires 30.8 kJ/ of heat, so 11.5g will need ..... (it's a proportion calculation.) Temperature does not change at BPt and is not relevant if the temp of the liquid is already at the BPt
ne definition of entropy is qrev/T, where qrev is the heat added in reversible operation (for complicated reasons pertaining to heat as a path function) and T is the temperature at which this is done.
Phase changes are particularly good examples for calculations of changes in entropy, since temperature will not change will the bonds of a state are being broken.
The calculations required boils down to:
1) finding the moles of benzene given from molar mass.
2) multiplying that moles by the heat of vaporization.
3)diving the heat energy required by the temperature of boiling point.</span>
Answer : The correct option is, 11.77 L
Solution : Given,
Mass of bromine gas = 84 g
Molar mass of bromine gas = 159.8 g/mole
First we have to calculate the moles of bromine gas.
Now we have to calculate the volume of bromine gas at STP.
As we know that at STP,
1 mole of bromine gas contains 22.4 L volume of bromine gas
So, 0.5256 mole of bromine gas contains 
volume of bromine gas
Therefore, the volume of bromine gas at STP is, 11.77 L
The answer is D. The rice cooker / pot.
hope this helps !
Explanation:
option 2) voltaic cells only
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