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Nina [5.8K]
4 years ago
6

A student found that the titration had taken 10.00 ml of 0.1002 m naoh to titration 0.132 g of aspirin, a monoprotic acid. calcu

late the percent purity of aspirin (c9h8o4, molar mass = 180.2 g/mol) sample.
Chemistry
2 answers:
Harman [31]4 years ago
4 0
The balanced equation for the reaction between NaOH and aspirin is as follows;
NaOH + C₉H₈O₄ --> C₉H₇O₄Na + H₂O
stoichiometry of NaOH to C₉H₈O₄ is 1:1
The number of NaOH moles reacted - 0.1002 M / 1000 mL/L x 10.00 mL 
Number of NaOH  moles - 0.001002 mol
Therefore number of moles of aspirin - 0.001002 mol
Mass of aspirin reacted - 0.001002 mol x 180.2 g/mol = 0.18 g
However the mass of the aspirin sample is 0.132 g but 0.18 g of aspirin has reacted, therefore this question is not correct.

lions [1.4K]4 years ago
3 0

Answer:

73.10% the percent purity of aspirin.

Explanation:

NaOH+HAsp\rightarrow NaAsp+H_2O

Moles of NaOH:

0.1002 M=\frac{\text{moles of NaOH}}{0.010 L}

Moles of NaOH = 0.001002 moles

According to reaction. 1 NaOH reacts with 1 mole of aspirin .

Then 0.001002 moles NaOH will reacts with :

\frac{1}{1}\times 0.001002 moles=0.001002 moles

Mass of 0.001002 moles of aspirin:

= 0.001002 moles × 180.2 g/mol = 0.18056 g

Percentage of purity of aspirin:

\%=\frac{0.132 g}{0.18056 g}\times 100=73.10\%

73.10% the percent purity of aspirin.

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Explanation:

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3 0
3 years ago
Toothpaste is an alkali. How could you use the toothpaste to show that red cabbage is an indicator?
Alecsey [184]

Answer:

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3 0
3 years ago
A 6.1-kg solid sphere, made of metal whose density is 2600 kg/m3, is suspended by a cord. When the sphere is immersed in a liqui
deff fn [24]

Answer:

Density of the liquid = 1470.43 kg/m³

Explanation:

Given:

Mass of solid sphere(m) = 6.1 kg

Density of the metal = 2600 kg/m³

Thus volume of the liquid :

Volume(V)=\frac{Mass(m)}{Density (\rho)}

Volume of the sphere = 6.1 kg/2600 kg/m³ = 0.002346 m³

The volume of water displaced is equal to the volume of sphere (Archimedes' principle)

Volume displaced = 0.002346 m³

Buoyant force =\rho\times gV

Where

\rho is the density of the fluid

g is the acceleration due to gravity

V is the volume displaced

The free body diagram of the sphere is shown in image.

According to image:

mg=\rho\times gV+T

Acceleration due to gravity = 9.81 ms⁻²

Tension force = 26 N

Applying in the equation to find the density of the liquid as:

6.1\times 9.81=\rho\times 9.81\times 0.002346+26

33.841=\rho\times 9.81\times 0.002346

\rho=\frac{33.841}{9.81\times 0.002346}

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<u>Thus, the density of the liquid = 1470.43 kg/m³</u>

6 0
4 years ago
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Daniel [21]

Answer:

1. False - compression

2. True

3. False - transform faults

4. False - horizontally

5. True

6. False- perpendicular

7. False - away from

8. False - increase

9. True

10. True

Explanation:

1. Mountains, oceanic trenches, and rift valleys are created by tension and compression stress. They are formed by divergent and convergent boundaries. Compression stress occurs when plates are pushing against each other, while tension stress occurs when the plates are pulling away from each other.

**Shear stress happens when the plates grind against each other. Often found in transform boundaries.

2. Transform faults happen when two plates glide or slide against each other. These areas are called transform boundaries. Transform faults occur in the ocean. When these boundaries are formed on land, they are called strike-slip faults.

3. Shear stress that occur in transform boundaries produce transform faults. These faults are usually identified by long faults and ridges. Sometimes small ponds form in the cracks due to deposition.

*** Rift valleys are produced by divergent boundaries or tension stress, when the plates are pulled apart.

4. Transform boundaries are formed when two plates slides against each other. Transform faults are formed in these boundaries and the movement of the plates are horizontal.

*** They do not move vertically.

5-6. Mid-oceanic ridges are segmented or divided by transform faults. The transform faults in the mid-oceanic ridges are perpendicular to the oceanic ridges. They separate them into distinct segments and can run across for hundreds of kilometers

7. New faults form as they move away from the ridges. Mid oceanic ridges are formed when the plates move apart, pushing the seafloor outwards and along with that, the transform faults. When new crust however overlaps the transform fault, they stop moving against each other, and start moving side by side, creating a crack.

8. Transform faults increase in size as long as the plates continue to move. The areas of transform faults, especially in the surface create earthquake faults.

9. Faults at the surface can be part of a larger underground system. Some faults can cut across continental crusts. These faults are created by different geological processes, like compression stress from convergent boundaries, tension stress from divergent boundaries, and shear stress from transform boundaries.

10. Fault zones are areas where you can find different faults formed, relatively close to each other. The faults in fault zones can be shallow or deeper like the fault zone Sierra Madre.

6 0
4 years ago
In the following reaction, 451.4 g of lead reacts with excess oxygen forming 365.0 g of lead(II) oxide. Calculate the percent yi
user100 [1]
Let MM(x) be the molar mass of x.

MM(Pb) : MM(PbO)
=207.21 : 223.20  =  451.4 g : x g

cross multiply and solve for x
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4 0
4 years ago
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