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Law Incorporation [45]
3 years ago
7

What is the ph of a buffer prepared by adding 1.00 l of 1.0 m hcℓ to 750 ml of 1.5 m nahcoo? ka = 1.7 x 10-4?

Chemistry
1 answer:
alexandr1967 [171]3 years ago
5 0
Ph = 2.837 ( solution is attached ) 

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This graph represents an endothermic reaction. What does it show about the potential energy of reactants and products? Abuzua nu
Nata [24]

Answer:

The potential energy of the products is greater than the potential energy of the reactants

Explanation:

i just took the test

6 0
3 years ago
Which salt is produced when NH4OH reacts with HNO3?<br> KNO2<br> NaNO3<br> NH4NO3<br> NH4NO2
xenn [34]

Answer:

NH4NO3 is the answer

Explanation:

Please mark as brainliest

4 0
3 years ago
Read 2 more answers
How many molecules of carbon dioxide are present in 4.81042 mol of that substance?
Korvikt [17]

1 mol is equal to 6.02×10∧23 molecules.

first put in the calculator 4.81042 × 6.02 then hit EXP or 2nd then EE. (Depends on the type of calculator). then put in 23 and press equal.

The calculator will says 2.89587284×10∧24.

So the answer will be 2.90×10∧24.

I mot sure if the 2.90 is correct but it is close to the answer. it really depends how you want to round it. As long as the decimals are close the answer doesn't matter. Hope this helps. Please mark as Brainliest.

4 0
4 years ago
Given the following at 25C calculate delta Hf for HCN (g) at 25C. 2NH3 (g) +3O2 (g) + 2CH4 (g) ---&gt; 2HCN (g) + 6H2O (g) delta
AysviL [449]

<u>Answer:</u> The \Delta H_f for HCN (g) in the reaction is 135.1 kJ/mol.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. The equation used to calculate enthalpy change is of a reaction is:

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

2NH_3(g)+3O_2(g)+2CH_4(g)\rightarrow 2HCN(g)+6H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(2\times \Delta H_f_{(HCN)})+(6\times \Delta H_f_{(H_2O)})]-[(2\times \Delta H_f_{(NH_3)})+(3\times \Delta H_f_{(O_2)})+(2\times \Delta H_f_{(CH_4)})]

We are given:

\Delta H_f_{(H_2O)}=-241.8kJ/mol\\\Delta H_f_{(NH_3)}=-80.3kJ/mol\\\Delta H_f_{(CH_4)}=-74.6kJ/mol\\\Delta H_f_{(O_2)}=0kJ/mol\\\Delta H_{rxn}=-870.8kJ

Putting values in above equation, we get:

-870.8=[(2\times \Delta H_f_{(HCN)})+(6\times (-241.8))]-[(2\times (-80.3))+(3\times (0))+(2\times (-74.6))]\\\\\Delta H_f_{(HCN)}=135.1kJ

Hence, the \Delta H_f for HCN (g) in the reaction is 135.1 kJ/mol.

8 0
3 years ago
A 45 kg box is sitting on a window ledge 2.0 m above the ground. What is the potential energy of the box?
Travka [436]

Answer:

<h3>The answer is 900 J</h3>

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

PE = 45 × 10 × 2

We have the final answer as

<h3>900 J</h3>

Hope this helps you

5 0
3 years ago
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