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steposvetlana [31]
3 years ago
13

Lin walk at a steady rate from school to the library. Lin can walk 12 miles in 4 hours. The library is two and a quarter miles a

way from the school. If she started walking at 3:15 pm, what time will she arrive at the library?
Mathematics
1 answer:
slamgirl [31]3 years ago
8 0

Answer:

4:30 pm

Step-by-step explanation:

Step one:

given data

distance= 12 mile

time=4 hours

speed= ?

Step two

speed= distance/time

Speed= 12/4

Speed= 3mile per hour

given that the library is 2.25 mile (2 and 1/4)

the time it will take at the speed of 3 mile per hour  is

time= 2.25/3

time=0.75hours= 1hour 15 min

start time= 3.15

time taken= 1:15

arrrival time= start + time taken = 4:30 pm

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Drag the correct steps into order to evaluate 42 + t6 for t = 12.
faltersainse [42]

Answer:

42+ (12)6=

42+72=114

Step-by-step explanation:

use pemdas to eliminate parethesis then add them together

7 0
3 years ago
A train left isiolo on Friday at 11:45 pm.it took 8 hrs 55 mins to reach Nairobi. When did the train reach Nairobi? A . Saturday
valentina_108 [34]

Answer:

D.Saturday 8:40am

Step-by-step explanation:

11+8=19 (7)

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one hour(100) makes 60 minutes

100-60=40

Therefore the answer is Saturday 8:40am

7 0
3 years ago
20 POINTS Find the diameter?? Pls help I dont know what to do..
Akimi4 [234]

Answer:

Diameter = 19.33

Step-by-step explanation:

Imaging a radius line from O to the endpoints of the 7. call this line R.

Label the part of the vertical line from O to the 90 degree intersection y.

Now you have a right triangle.

Using the Pythagorean theorem:

R² = 7² + y²

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R² = 49 + (R-3)²

R² = 49 + R² - 6R + 9

simplify:

0 = 58 - 6R

6R = 58

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7 0
3 years ago
Find an equation of the line described (3,7) (0,0)
Colt1911 [192]
The formula of the line is
y=mx + b
The likes goes through the point (0,0)
that means that y-int = 0, b=0
y=mx
So we need to find only slope.

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So, y= \frac{7}{3} x



3 0
3 years ago
Solve the following problems. a. 2 ft. 5 in. + 9 in. b. 4 yd. 8 in + 6 yd. 6 in. c. 29 yd. 2 ft. 11 in. + 55 yd. 1 ft. 10 in. +
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<span>a. 2 ft. 5 in. + 9 in.=2 ft 14 in.=2 ft. (12+2) in.=3 ft. 2 in. (since 1 ft.=12 in.);
</span>
<span> b. 4 yd. 8 in + 6 yd. 6 in. =(4+6) yd. (8+6) in.=10 yd. 14 in.=10 yd. (12+2) in.=10 yd. 1 ft. 2 in.;
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<span>c. 29 yd. 2 ft. 11 in. + 55 yd. 1 ft. 10 in. + 13 yd. 1 ft. 3 in.=(29+55+13) yd. (2+1+1) ft. (11+10+3) in.=97 yd. 4 ft. 24 in.=97 yd. (3+1)  ft. (12+12) in.=98 yd. 3 ft.=99 yd.
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d. 4,839 sq. yd. 8 sq. ft. 139 sq. in. + 7 sq. ft. 124 sq. in.=4,839 sq. yd. (8+7) sq. ft. (139+124) sq. in.=<span>4,839 sq. yd. 15 sq. ft. 263 sq. in. =</span>
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4 0
3 years ago
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