All categories

3 years ago

Which is smaller-21/35, 7/5

Mathematics

2 answers:

stiks02 [169]3 years ago

6 0

-21/35 is larger than 7/5, because 7/5 could be simplified and be more than 1, while -21/35 would be a decimal.

Paladinen [302]3 years ago

3 0

Answer:

-21/35

Step-by-step explanation:

So, 7/5 is a postive number, since it doesn't have a negative - sign in front of it. On the other hand, -21/35 does. Knowing this, we can conclude that -21/35 is smaller than 7/5.

If you want another way of thinking about it, just guessing, what is 7/5? Well, 7 is bigger than 5, so it must be at least 1. On the other hand, with -21/35, the -21 doesnt look like its bigger than 35, so it must be smaller than 1.

Answer:

-21/35 is smaller than 7/5

Ti⊂k∫∈s ω∅∅p

You might be interested in

How can the logarithmic expression be rewritten? Select True or False for each statement.

topjm [15]

Answer:

True, True, False

Step-by-step explanation:

5 0

2 years ago

Use a graphing device to find all solutions of the equation, rounded to two decimal places. (enter your answers as a comma-separ

attashe74 [19]

The solutions are
x = 0.01, 1.47

5 0

3 years ago

What could be the answer to my question in my maths work : 4.5 x 0.2

KATRIN_1 [288]

The answer issssssss 0.9

3 0

3 years ago

There are three urns that each contain 10 balls. The first contains 3 white and 7 red balls, the second 8 white and 2 red, and t

malfutka [58]

Answer:

(a) 0.0520

(b) 0.3699

Step-by-step explanation:

Let $E_{1},E_{2},E_{3}$ be the events of selecting urn 1, urn 2 and urn 3 respectively.

So, $P(E_{1})=P(E_{2})=P(E_{3})=\frac{1}{3}$

Let W be the event of drawing a white ball.

Now, probability of drawing 2 white balls from urn 1 is given as:

$P(W\cap W \cap E_{1})=P(E_{1})\times P((W\cap W)/E_{1})\\P(W\cap W \cap E_{1})=\frac{1}{3}\times (\frac{3}{10})^{2}=\frac{9}{300}$

Probability of drawing 2 white balls from urn 2 is given as:

$P(W\cap W \cap E_{2})=P(E_{2})\times P((W\cap W)/E_{2})\\P(W\cap W \cap E_{2})=\frac{1}{3}\times (\frac{8}{10})^{2}=\frac{64}{300}$

Probability of drawing 2 white balls from urn 3 is given as:

$P(W\cap W \cap E_{3})=P(E_{2})\times P((W\cap W)/E_{2})=\frac{1}{3}\times 1=\frac{1}{3}$ ............. (as all balls are white only)

Now, probability of drawing 2 white balls is the sum of all the above probabilities and is given as:

$P(2W)=P(W\cap W \cap E_{1})+P(W\cap W \cap E_{2})+P(W\cap W \cap E_{3})\\P(2W)=\frac{9}{300}+\frac{64}{300}+\frac{1}{3}\\P(2W)=\frac{9}{300}+\frac{64}{300}+\frac{100}{300}=\frac{9+64+100}{300}=\frac{173}{300}$

(a)

Probability of selecting urn 1 given that 2 white balls are drawn is:

$P(E_{1}/2W)=\frac{P(E_{1})\times P(2W/E_{1})}{P(2W)}\\P(E_{1}/2W)=\frac{\frac{9}{300}}{\frac{173}{300}}=\frac{9}{173}=0.0520$

Therefore, probability of selecting urn 1 given that 2 white balls are drawn is 0.0250.

(b)

Probability of selecting urn 2 given that 2 white balls are drawn is:

$P(E_{2}/2W)=\frac{P(E_{2})\times P(2W/E_{2})}{P(2W)}\\P(E_{2}/2W)=\frac{\frac{64}{300}}{\frac{173}{300}}=\frac{64}{173}=0.3699$

Therefore, probability of selecting urn 2 given that 2 white balls are drawn is 0.3699

8 0

4 years ago

two trains leave a station at the same time. One train returns to the station in 45 minutes and leaves again. The other train re

Darya [45]

6,750 I think is the right answer

8 0

4 years ago

Which is smaller-21/35, 7/5​

Which is smaller-21/35, 7/5