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2 years ago

Suppose a line has slope 4 and passes through the point (-2, 5). Which other point must also be on the graph?

1 answer:

6 0

(1,9) and the y-intercept would be (0,13). There's this amazing website called desmos.com it is an online graphing calculator, it will graph equations for you and all that whether it be in slope intercept form, or point intercept form, or standard intercept form.

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HELP PLEASEE!!!!

ss7ja [257]

Answer:

See below ~

Step-by-step explanation:

$\textsf {Each of the steps has been reasoned below :}$

$\implies \textsf {3x - 2 = 4 (Given)}$

$\implies \textsf {3x = 6 (Addition Property of Equality)}$

$\implies \textsf {x = 2 (Division Property of Equality)}$

$\textsf {In the second step, the property has been applied}\\\textsf {by adding 2 to each side of the equation.}$

$\textsf {In the third step, the property has been applied by dividing 3 on each side.}$

3 0

2 years ago

Read 2 more answers

What is the slope formula?

Ksivusya [100]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Evaluate the following f(-2)+f(-3)=

8090 [49]

It would be =-5f
Hope this helps

7 0

3 years ago

When David was asked how old he was, he said " I'm three times younger than my dad, but twice as old as Rebecca. " Then little R

daser333 [38]

Using a system of equations, it is found that David is 12 years old.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

The variables are given as follows:

Variable x: David's age.

Variable y: Dad's age.

Variable z: Rebecca's age.

David is three times younger than the dad and twice as old as Rebecca, then:

x = y/3 -> y = 3x.

x = 2z.

Rebecca is 30 years younger than the dad, hence:

z = y - 30.

Then, since x = 2z and z = y - 30 and y = 3x, we solve for x to find David's age.

x = 2(y - 30)

x = 2(3x - 30)

x = 6x - 60

5x = 60

x = 60/5

x = 12.

David is 12 years old.

More can be learned about a system of equations at brainly.com/question/24342899

#SPJ1

8 0

1 year ago

If D is midpoint of side BC of triangle ABC. P and Q are points lying respectively on side AB and AC such that DP is parallel to

LUCKY_DIMON [66]

See proof below

Step-by-step explanation:

Assume triangle ABC to have vertices at;

A(2,-1), B(2,-7) and C(6,-7)

D is midpoint of BC, thus D is at (4,-7)

The P and Q, are lying on side AB and AC, hence assume P is at (2,-4) and Q is at (4,-4) such at DP is parallel to QA

Plot the points on a graph tool and join the points to view the sketch.

To prove area of triangle CPQ is 1/4 area of ABC will be;

Find area ABC and CPQ then compare the areas.

Apply the distance formula to find the length of sides of the triangles then find the areas.

The distance formula is;

$d=\sqrt{x_2-x_1)^2+(y_2-y_1)^2}$

Length of side AB from the sketch is;

$AB=\sqrt{(2-2)^2+(-7--1)^2} =\sqrt{-6^2} =\sqrt{36} =6units$

Length of side BC will be;

$BC=\sqrt{(-7--7)^2+(6-2)^2} =\sqrt{4^2} =\sqrt{16} =4units$

Thus area of triangle ABC will be;

1/2 *base length*height ------because it is a right-triangle

1/2*4*6=12 square units

Find the lengths of all sides of triangle CPQ

Length of side PQ is half that of side BC thus PQ=2 units

Length of side PC is;

$PC=\sqrt{(6-2)^2+(-7--4)^2} =\sqrt{4^2+-3^2} =\sqrt{16+9} =\sqrt{25} =5units$

Length of side QC will be;

$QC=\sqrt{(6-4)^2+(-7--4)^2} =\sqrt{2^2+-3^3} =\sqrt{4+9} =\sqrt{13}$

QC= √13 = 3.6 units

Find area of triangle CPQ given all sides by applying the Heron's formula for area of triangle which is;

A=√s(s-a)(s-b)(s-c) where;

A=area of the triangle

s= half the perimeter of the triangle

a=side PQ = 2 units

b=side PC = 5 units

c= side QC = 3.6 units

Finding the perimeter of triangle CPQ will be;

P=sum of all sides

P=2+5+3.6 =10.6 units

s=10.6/2 = 5.3

Area of the triangle CPQ will be;

$A=\sqrt{5.3(5.3-2)(5.3-5)(5.3-3.6)} \\A=\sqrt{5.3(3.3)(0.3)(1.7)} \\A=\sqrt{8.9} =2.98$

A=3.0 (1 decimal place)

Compare the areas;

Area of triangle ABC=12 square units

Area of triangle CPQ = 3 square units

Area of triangle CPQ / Area of triangle ABC = 3/12 =1/4

Thus you have proved that area of triangle CPQ is 1/4 th area of triangle ABC because 1/4 *12 =3

Learn More

Area of a triangle ;brainly.com/question/14869984

The Heron's formula : brainly.com/question/10713495

Keywords: midpoint, triangle, sides, parallel, prove , area, equal

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6 0

3 years ago