Answer:
9 and 10
Step-by-step explanation:
To start, let's have what we know:
a and b are two consecutive positive integers
a = first integer
b = second integer, 1 greater than variable a
b = a + 1
b^2 = 19 + 9a
To solve this, we would only have to substitute values in
b^2 = 19 + 9a
(a+1)^2 = 19 + 9a
a^2 + 2a +1 = 19 + 9a
-9a -19 -19 - 9a
a^2 -7a - 18 = 0
a^2 + 2a - 9a - 18
a(a + 2) - 9(a+2) = 0
(a - 9)(a + 2) = 0
So solving this, we would get a = 9 or a = -2. Since this is supposed to be a positive integer, a will be 9.
Solving for b,
b = a + 1
= 9 + 1
= 10
Let me know in the comments if you have any questions! If you could mark this answer as brainliest, I would very much appreciate it!
52 thousandths is 0.052.
We'll move the decimal point twice to the right, then move it back with the multiplication of 10 to the negative second power.
The answer is 5.2 · 10⁻².
The answer is 76.76
Fort you have to find 28% of 292.
28/100 = x/292
100x= 292 x 28
100x = 8176
x= 81.76
Then you have to subtract 5 from 81.76
81.76 - 5 = 76.76
A)
x = # of students in math class
2x+7=40
B)
2x+7=40
-7
------------
2x = 33
--- ---
2 2
x = 76 students
Sorry if it's hard to read. I tried my best. Hope I helped.