Answer:
We know that:
H(x) = |1 - x^3|
and:
We want to write H(x) as f( g(x) ) , such that for two functions:
So we want to find two functions f(x) and g(x) such that:
f( g(x) ) = |1 - x^3|
Where neither of these functions can be an identity function.
Let's define g(x) as:
g(x) = x^3 + 2
And f(x) as:
f(x) = | A - x|
Where A can be a real number, we need to find the value of A.
Then:
f(g(x)) = |A - g(x)|
and remember that g(x) = x^3 + 2
then:
f(g(x)) = |A - g(x)| = |A - x^3 - 2|
And this must be equal to:
|A - x^3 - 2| = |1 - x^3|
Then:
A = 3
The functions are then:
f(x) = | 3 - x|
g(x) = x^3 + 2
And H(x) = f( g(x) )
To get the midsegment, namely HN, well, we need H and N
hmm so.... notice the picture you have there, is just an "isosceles trapezoid", namely, it has two equal sides, the left and right one, namely JL and KM
the midpoint of JL is H and the midpoint of KM is N
thus


![\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) K&({{ 4q}}\quad ,&{{ 4n}})\quad % (c,d) M&({{ 4p}}\quad ,&{{ 0}}) \end{array}\qquad % coordinates of midpoint \left(\cfrac{4p+4q}{2}\quad ,\quad \cfrac{0+4n}{2} \right) \\\\\\ \left( \cfrac{2(2p+2q)}{2},\cfrac{4n}{2} \right)\implies \boxed{[(2p+2q), 2n]\impliedby N}\\\\ -----------------------------\\\\](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Blllll%7D%0A%26x_1%26y_1%26x_2%26y_2%5C%5C%0A%25%20%20%28a%2Cb%29%0AK%26%28%7B%7B%204q%7D%7D%5Cquad%20%2C%26%7B%7B%204n%7D%7D%29%5Cquad%20%0A%25%20%20%28c%2Cd%29%0AM%26%28%7B%7B%204p%7D%7D%5Cquad%20%2C%26%7B%7B%200%7D%7D%29%0A%5Cend%7Barray%7D%5Cqquad%0A%25%20%20%20coordinates%20of%20midpoint%20%0A%5Cleft%28%5Ccfrac%7B4p%2B4q%7D%7B2%7D%5Cquad%20%2C%5Cquad%20%5Ccfrac%7B0%2B4n%7D%7B2%7D%20%5Cright%29%0A%5C%5C%5C%5C%5C%5C%0A%5Cleft%28%20%5Ccfrac%7B2%282p%2B2q%29%7D%7B2%7D%2C%5Ccfrac%7B4n%7D%7B2%7D%20%5Cright%29%5Cimplies%20%5Cboxed%7B%5B%282p%2B2q%29%2C%202n%5D%5Cimpliedby%20N%7D%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C)
Answer:
a. -16 is the constant
b.if you expand the equation it would be x^2-16, and the constant is -16
Answer:
C and E are yes, A, B, and D are no
Step-by-step explanation:
8x2x3 = 48
for c, 4x4x3 = 48
e, 6x2x4 = 48