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Anna [14]
2 years ago
15

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

Mathematics
1 answer:
sammy [17]2 years ago
8 0

Step-by-step explanation:

value of bda is 125 and bca is 110 may it helps u

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Express the function H in the form f ∘ g. (Enter your answers as a comma-separated list. Use non-identity functions forf(x) and
wolverine [178]

Answer:

We know that:

H(x) = |1 - x^3|

and:

We want to write H(x) as  f( g(x) ) , such that for two functions:

So we want to find two functions f(x) and g(x) such that:

f( g(x) ) = |1 - x^3|

Where neither of these functions can be an identity function.

Let's define g(x) as:

g(x) = x^3 + 2

And f(x) as:

f(x) = | A - x|

Where A can be a real number, we need to find the value of A.

Then:

f(g(x)) = |A - g(x)|

and remember that g(x) = x^3 + 2

then:

f(g(x)) = |A - g(x)| = |A - x^3 - 2|

And this must be equal to:

|A - x^3 - 2| =  |1 - x^3|

Then:

A = 3

The functions are then:

f(x) = | 3 - x|

g(x) = x^3 + 2

And H(x) =  f( g(x) )

6 0
3 years ago
Help on A and B please
weqwewe [10]

Answer:

b bbbbbbbbbbb

3 0
3 years ago
The vertices of the trapezoid are J(4m, 4n), K(4q, 4n), M(4p, 0), and L(0, 0). Find the midpoint of the midsegment of the trapez
Lilit [14]
To get the midsegment, namely HN, well, we need H and N

hmm so....  notice the picture you have there, is just an "isosceles trapezoid", namely, it has two equal sides, the left and right one, namely JL and KM

the midpoint of JL is H and the midpoint of KM is N

thus

\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ \square}}\quad ,&{{ \square}})\quad 
%  (c,d)
&({{ \square}}\quad ,&{{ \square}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)\\\\
-----------------------------\\\\

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
J&({{ 4m}}\quad ,&{{ 4n}})\quad 
%  (c,d)
L&({{ 0}}\quad ,&{{ 0}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{0+4m}{2}\quad ,\quad \cfrac{0+4n}{2} \right)
\\\\\\
\left( \cfrac{4m}{2},\cfrac{4n}{2} \right)\implies \boxed{(2m,2n)\impliedby H}\\\\
-----------------------------\\\\

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
K&({{ 4q}}\quad ,&{{ 4n}})\quad 
%  (c,d)
M&({{ 4p}}\quad ,&{{ 0}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{4p+4q}{2}\quad ,\quad \cfrac{0+4n}{2} \right)
\\\\\\
\left( \cfrac{2(2p+2q)}{2},\cfrac{4n}{2} \right)\implies \boxed{[(2p+2q), 2n]\impliedby N}\\\\
-----------------------------\\\\

\bf \textit{so, the midpoint of HN is }
\\\\\\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
H&({{ 2m}}\quad ,&{{ 2n}})\quad 
%  (c,d)
N&({{ 2p+2q}}\quad ,&{{ 2n}})
\end{array}\\\\\\
%   coordinates of midpoint 
\left(\cfrac{(2p+2q)+2m}{2}\quad ,\quad \cfrac{2n+2n}{2} \right)
\\\\\\
\left( \cfrac{2(p+q+m)}{2},\cfrac{4n}{2} \right)\implies (p+q+m)\quad ,\quad 2n
5 0
3 years ago
Read 2 more answers
Tyler incorrectly says that the constant term of (x + 4)(x - 4) is zero.
svp [43]

Answer:

a. -16 is the constant

b.if you expand the equation it would be x^2-16, and the constant is -16

4 0
3 years ago
Justin has a crate that is 8 feet long, 2 feet wide, and 3 feel tall. Decide wether each of the crate sized described below has
blsea [12.9K]

Answer:

C and E are yes, A, B, and D are no

Step-by-step explanation:

8x2x3 = 48

for c, 4x4x3 = 48

e, 6x2x4 = 48

4 0
3 years ago
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