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3 years ago

12

Mauri’s little Sister weighed exactly 7 pounds when she was born. How many ounces did she weigh?

2 answers:

Goshia [24]3 years ago

8 0

Answer:

112 ounces

Step-by-step explanation:

Converting pounds to ounces is simple. Since there are exactly 16 ounces in one pound, just multiply the number of pounds by 16.

16

x. 7

------------

112

elixir [45]3 years ago

6 0

Searched it up on goggle

112

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Please help me, 6th grade math

Stells [14]

Answer:

Mean: 3.2 Median: 3.2 Mode:3.1 Range:0.5

Step-by-step explanation:

Easy.

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3 years ago

Give me the best answer

Nadya [2.5K]

After rewriting all sets of data from smaller to greater, I found that the last series is the one that is represented by the plot box:

79,86,88,88,92,98,100,106,115,136

Why? Because The median is 95 (like the box)

because the outliers are > 115 (up to 136)
because their is no outlier on the left by the mini value of 79

7 0

3 years ago

Hii can someone help with this pls :)

BlackZzzverrR [31]

Answer:

$R(x,y) = (0.8,-1.2)$

Step-by-step explanation:

The coordinates of QS are:

$Q(x_1,y_1) = (-2,-6)$

$S(x_2,y_2) = (5,6)$

The ratio is represented as:

$R_{m:n} = 2:3$

Required

Find the coordinates of R

The coordinates of R is calculated by:

$R(x,y) = (\frac{mx_2 + nx_1}{m+n},\frac{my_2 + ny_1}{m+n})$

Substitute values for m, n, x's and y's

$R(x,y) = (\frac{2 * 5 + 3 * -2}{2+3},\frac{2*6 + 3*-6}{2+3})$

$R(x,y) = (\frac{4}{5},\frac{-6}{5})$

$R(x,y) = (0.8,-1.2)$

<em>None of the options is correct</em>

6 0

3 years ago

Determine any data values that are missing from the tablo, assuming that the data represent a linear function.

mina [271]

Answer:

B.

Step-by-step explanation:

Missing xx:1 Missing y:5

7 0

3 years ago

(a) Find a 90% confidence interval for the population mean price (per 100 pounds) that farmers in this region get for their wate

Anon25 [30]

Answer:

The margin of error (E) $=0.49$

Step-by-step explanation:

Given,

mean $\bar{x}=6.88$

standard deviation $\sigma=1.90$

sample size $n=41$

$90\% \quad \text{confidence interval}$

Critical value $=\frac{z_\alpha}{2}\quad \quad\quad[\because\;\alpha=1-\text{confidence interval}]$

$=1-0.90$

$\Rightarrow \alpha=0.1$

Critical value $=\frac{z_{0.1}}{2}$

$=z_{0.05}$

$=1.645$

The margin of error (E) $=\frac{z_\alpha}{2} \times\frac{\sigma}{\sqrt{n} }$

$=1.645\times\frac{1.90}{\sqrt{41} }$

$=0.49$

Hence, The margin of error (E) $=0.49$

Complete question is attached in below.

7 0

3 years ago