Question

Question 2 of my ready pretty easy question im just dumb

Answer 1

Answer:

I think the answer is B.

Step-by-step explanation:

Answer 2

Answer:

D

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

x² + y² = z² , substitute values

4² + y² = ($\sqrt{137}$ )², that is

16 + y² = 137 ( subtract 16 from both sides )

y² = 121 ( take the square root of both sides )

y = $\sqrt{121}$ = 11 → D