Question 2 of my ready pretty easy question im just dumb

Mathematics

2 answers:

anygoal [31]3 years ago

3 0

Answer:

I think the answer is B.

Step-by-step explanation:

Ksju [112]3 years ago

3 0

Answer:

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

x² + y² = z² , substitute values

4² + y² = ( $\sqrt{137}$ )², that is

16 + y² = 137 ( subtract 16 from both sides )

y² = 121 ( take the square root of both sides )

y = $\sqrt{121}$ = 11 → D

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azamat

Answer:

$\large \boxed{y = (x - 5)^{2} + 2 }$

Step-by-step explanation:

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$\begin{array}{rcll}y & = & x^{2} - 10x + 27 & \\y - 27 & = & x^{2} - 10x & \text{Subtracted 27 from each side}\\y - 27&= & x^{2} - 10x + 25 - 25 & \text{Added and subtracted (b/2)}^{2}\\y - 27&= & (x - 5)^{2} - 25 & \text{Wrote the first three terms as the square of a binomial}\\y& = & \mathbf{(x - 5)^{2} + 2} & \text{Added 27 to each side}\\\end{array}\\\text{The vertex form of the parabola is $\large \boxed{\mathbf{y = (x - 5)^{2} + 2 }}$}$ The figure below shows that your parabola has its vertex at (5,2).