Answer:
{x,y} = {-2,-3}
Step-by-step explanation:
System of Linear Equations entered :
[1] -9x + 4y = 6
[2] 9x + 5y = -33
Graphic Representation of the Equations :
4y - 9x = 6 5y + 9x = -33
Solve by Substitution :
// Solve equation [2] for the variable y
[2] 5y = -9x - 33
[2] y = -9x/5 - 33/5
// Plug this in for variable y in equation [1]
[1] -9x + 4•(-9x/5-33/5) = 6
[1] -81x/5 = 162/5
[1] -81x = 162
// Solve equation [1] for the variable x
[1] 81x = - 162
[1] x = - 2
// By now we know this much :
x = -2
y = -9x/5-33/5
// Use the x value to solve for y
y = -(9/5)(-2)-33/5 = -3
My answer -
<span>1. Use symbols (not words) to express quotient
2. Use exponent symbol (^) to denote exponents
3. Just write out question number, question, and choices. No need for
extra information (such as points). Also, don't leave blank lines
between choices. This extraneous that we don't need just makes your
whole question very very long, and means a lot of scrolling on our part.
4. You should only post 2 or 3 questions at a time.
1) (6x^3 − 18x^2 − 12x) / (−6x) = −x^2 + 3x + 2 ----> so much simpler to read !
2) (d^7 g^13) / (d^2 g^7) = d^(7−2) g^(13−7) = d^5 g^6 ----> much easier to read !
3) (4x − 6)^2 = 16x^2 − 24x − 24x + 36 = 16x^2 − 48x + 36
4) (x^2 / y^5)^4 = (x^2)^4 / (y^5)^4 = x^8 / y^20
5) (3x + 5y)(4x − 3y) = 12x^2 − 9xy + 20xy − 15y^2 = 12x^2 + 11xy − 15y^2
6) (3x^3y^4z^4)(2x^3y^4z^2) = (3*2) x^(3+3) y^(4+4) z^(4+2) = 6 x^6 y^8 z^6
7) 5x + 3x^4 − 7x^3 ----> Fourth degree trinomial
8) (5x^3 − 5x − 8) + (2x^3 + 4x + 2) = 7x^3 − x − 6
9) (x − 1) + (2x + 5) − (x + 3) = x + 1
10) (−4g^8h^5k^2)0(hk^2)^2 = 0 (anything multiplied by 0 = 0)
or.. (−4g^8h^5k^2)^0(hk^2)^2 = 1 (h^2 (k^2)^2) = h^2 k^4
Last question shows why it is so important to use proper symbols (such
as ^ to indicate exponents). Without such symbols, I could not tell if
the 0 was an actual number and part of multiplication, of if 0 was an
exponent of the expression preceding it.
P.S
Glad to help you have an AWESOME!!! day :)
</span>
Answer:
Y=7
Step-by-step explanation:
(3y+5)= -4 -8y +9 + 77
-5 -5
3y= -9 - 8y + 9 + 77
+9 -9
3y= -8y + 77
+8y +8y
11y = 77
11y/11 77/11
y = 7
1. subtract 5 from both sides
2. add -9 and +9 and you get 0
3. add 8y to both sides
4. divide both sides by 11
5. you get y=7
