Answer:
50
Step-by-step explanation:
24x2=48
48+2=50
Calculate the probability that both bids are successful
Answer:
The probability that both contracs are successful is 0.21
Step-by-step explanation:
Given
E1 = the event that the bid on the first contract is successful
E2 = the event that the bid on the second contract is successful
P(E1) = 0.3
P(E2) = 0.7
Let P(A) represent the event that both contracts are successful
P(A) = P(E1 and E2)
Since both events are independent. P(A) becomes
P(A) = = P(E1 * P(E2)
By substituton
P(A) = 0.3 * 0.7
P(A) = 0.21
Hence the probability that both contracs are successful is 0.21
Answer:
(a) and are indeed mutually-exclusive.
(b) , whereas .
(c) .
(d) , whereas
Step-by-step explanation:
<h3>(a)</h3>
means that it is impossible for events and to happen at the same time. Therefore, event and are mutually-exclusive.
<h3>(b)</h3>
By the definition of conditional probability:
.
Rearrange to obtain:
.
Similarly:
.
<h3>(c)</h3>
Note that:
.
In other words, and are collectively-exhaustive. Since and are collectively-exhaustive and mutually-exclusive at the same time:
.
<h3>(d)</h3>
By Bayes' Theorem:
.
Similarly:
.
Answer:
It is ASA congruence rule as the 2 angles and the included side of the triangle are equal
The 114 represents 80% of the total price before the sale. You would set up your equation as
Cost Price * 80% = Sale Price.
Sale Price = 114
80% = 80/100 = 0.8
Cost Price = 114/0.8
Cost Price = 142.50 which is the price before the deduction. You can confirm this by taking 20% of 142.50 and subtracting it form 142.50
20% * 142.50
20/100 * 142.50
2850/100
28.50
Now subtract 28.50 from 142.50
142.50 - 28.50 = 114 which is just what you might expect.