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Anna007 [38]
3 years ago
5

Select the correct answer. Function f is an exponential function that has an initial value of 64 and decreases by 50% as x incre

ases by 1 unit. Function g is represented by the table. x 0 1 2 3 4 g(x) 75 43 27 19 15 Which statement correctly compares the two functions on the interval [0, 4]? A. Both functions are decreasing, but function f is decreasing at a faster average rate on that interval. B. Both functions are decreasing, but function g is decreasing at a faster average rate on that interval. C. Function f is decreasing, but function g is increasing, on that interval. D. Both functions are decreasing at the same average rate on that interval.
Mathematics
2 answers:
lozanna [386]3 years ago
3 0

9514 1404 393

Answer:

  D. Both functions are decreasing at the same average rate on that interval

Step-by-step explanation:

The dashed lines on the attached graph of the two functions (f in red, g in purple) represent the average rate of change of each function on the interval. The lines are parallel, because the average rate of change is the same for each of the functions on that interval.

__

Function f decreases by 60 units from f(0) = 64 to f(4) = 4 on the interval x = [0, 4]. Function g decreases by 60 units from g(0) = 75 to g(4) = 15 on the same interval. The average rate of change is the amount of decrease divided by the interval width. Those values are the same for both functions.

Lerok [7]3 years ago
3 0

Answer:

Imma just answer this for no reason because she won't look back at answers

Step-by-step explanation:

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5x - 3y = -13

5x - 3(15x + 6) = -13 <== the new equation

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In the trepezium,a=7cm,b=10.4cm and h=6.7cm.work out the area of the trepezium.​
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58.29

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bija089 [108]

Part A:

The average rate of change refers to a function's slope. Thus, we are going to need to use the slope formula, which is:

m = \dfrac{y_2 - y_1}{x_2 - x_1}

  • (x_1, y_1) and (x_2, y_2) are points on the function

You can see that we are given the x-values for our interval, but we are not given the y-values, which means that we will need to find them ourselves. Remember that the y-values of functions refers to the outputs of the function, so to find the y-values simply use your given x-value in the function and observe the result:

h(0) = 3(5)^0 = 3 \cdot 1 = 3

h(1) = 3(5)^1 = 3 \cdot 5 = 15

h(2) = 3(5)^2 = 3 \cdot 25 = 75

h(3) = 3(5)^3 = 3 \cdot 125 = 375


Now, let's find the slopes for each of the sections of the function:

<u>Section A</u>

m = \dfrac{15 - 3}{1 - 0} = \boxed{12}

<u>Section B</u>

m = \dfrac{375 - 75}{3 - 2} = \boxed{300}


Part B:

In this case, we can find how many times greater the rate of change in Section B is by dividing the slopes together.

\dfrac{m_B}{m_A} = \dfrac{300}{12} = 25


It is 25 times greater. This is because 3(5)^x is an exponential growth function, which grows faster and faster as the x-values get higher and higher. This is unlike a linear function which grows or declines at a constant rate.

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