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Cerrena [4.2K]
3 years ago
8

B. 40 is 160% of what number?

Mathematics
1 answer:
Anton [14]3 years ago
6 0

Answer:

25

Step-by-step explanation:

the question basically translates to

160% x n =40  

a little trick with percents I use is that the word "of" always means multiplication.

n=40/160%=25

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I will give it to you in order 2 5 9 4 10 3 6 7 8 1 10 7 3 9 8 5 1 4 2 6 5 1 3 6 4 9 2 5 7 8
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3 years ago
A fraction reduces to 36. If its denominator is 6x^5, what it's its numerator?
earnstyle [38]
The answer is B because you will  cancel the x^5 part on top and bottom and the numerator left 6^3 and denominator left 6
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6 0
3 years ago
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Which layer of the atmosphere reflects radio waves back to Earth? Mesosphere Stratosphere Thermosphere Troposphere BRAINLEST
nataly862011 [7]

Answer:

ionosphere

Step-by-step explanation:

In radio communication, skywave or skip refers to the propagation of radio waves reflected or refracted back toward Earth from the ionosphere, an electrically charged layer of the upper atmosphere

6 0
3 years ago
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Reagan uses 2 3/4 cups of vinegar in her salad dressing recipe. How much vinegar would Reagan use to make 5 recipes?
igor_vitrenko [27]

Answer:

13 3/4

Step-by-step explanation:

2 3/4 is 11/4 when converted into an improper fraction.

5 is 5/1 when converted into a fraction.

11*5 is 55 (numerators)

4*1 is 4 (denominators)

55/4 is 13 with 3/4 remaining

13 3/4

5 0
3 years ago
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While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
3 years ago
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