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mina [271]
3 years ago
10

Here's yet another coordinates problem! Please solve ASAP if you can. Thank you all very much! :)

Mathematics
1 answer:
Olegator [25]3 years ago
7 0
(0,0) is the cost of 0 bags of peanuts. This is because the x-axis is labeled "Bags of Peanuts", and an x-value of 0 implies 0 bags of peanuts.
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Write x^2-12+19 in the form (x+a)^2+b
Westkost [7]

Answer:

(x-6)^2 -17

hope it helps

8 0
3 years ago
Identify the inverse g(x) of the given relation f(x).
Alekssandra [29.7K]

Answer:

D

Step-by-step explanation:

Given (x, y) is a point on f(x), then the corresponding point on the inverse g(x) is (y, x)

Hence

(8, 3) → (3, 8)

(4, 1) → (1, 4)

(0, - 1) → (- 1, 0)

(- 4, - 3) → (- 3, - 4)

That is the last set of points represents g(x)

4 0
4 years ago
A caterer charges a $30 fee plus an additional $6.50 per person. She determines the total cost, C, for x people by using the equ
emmainna [20.7K]

Answer:

$550

Step-by-step explanation:

In this question, we have to find how much a party would cost for 80 people.

We know that our equation is C = 6.50x + 30

"x" is the amount of people.

To found our answer, we would plug in 80 to "x" to find the total cost.

Solve:

C = 6.50(80) + 30

C = 520 + 30

C = 550

This means that the cost of the party for 80 people would be $550.

3 0
3 years ago
Factor the expression: x^6-729. Show your work Please.
Brut [27]

Answer:

  • (x + 3)(x - 3)(x^2 -3x + 9)(x^2 + 3x + 9)

Step-by-step explanation:

<u><em>Use of formulas:</em></u>

  • <em>a^2 - b^2 = (a + b)(a -b)</em>
  • <em>a^3 + b^3 = (a + b)(a^2 - ab + b^2)</em>
  • <em>a^3 - b^3 = (a - b)(a^2 + ab + b^2)</em>

<u>Given the expression: </u>

  • x^6-729

<u>Factoring 729</u>

  • 729 = 3*3*3*3*3*3 = 3^6

<u>Factoring the expression </u>

  • x^6 - 3^6 =
  • (x^3)^2 - (3^3)^2 =
  • (x^3 + 3^3)(x^3 - 3^3) =
  • (x + 3)(x^2 -3x + 9)(x - 3)(x^2 + 3x + 9) =
  • (x + 3)(x - 3)(x^2 -3x + 9)(x^2 + 3x + 9)
7 0
3 years ago
What do you think the answer is?
spin [16.1K]
C. $17.28
1.92•9=17.28
4 0
3 years ago
Read 2 more answers
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