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Leno4ka [110]
3 years ago
8

Decide which of the two given prices is the better deal and explain why. You can buy shampoo in a ​6-ounce bottle for ​$2.29 or

in a ​15-ounce bottle for ​$.10.19
Mathematics
1 answer:
hichkok12 [17]3 years ago
3 0

Answer:

The 6 oz bottle

Step-by-step explanation:

When you simplify it to see how much per ounce each costs, the 6-oz has the better price.

2.29/6 = 0.381666....

10.19/15 = 0.6793....

the second bottle cost more per ounce, so the 6 oz bottle has the better deal

*plz brainlist

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What is the mean of the numbers 6 4 9 6 7 10 7​
Paha777 [63]

Step-by-step explanation:

Mean =sum of values /number of values

total sum ↪️ 6+4+9+6+7+10+7

number of values is 7

= 49/7

<h2> = 7 is themean</h2>
6 0
2 years ago
Name the angle in four ways. Then classify the angle as acute,right,obtuse, or straight.
kirill115 [55]

Answer:

∡RST

∡S

∡TSR

∡4

this appears to be an obtuse angle

Step-by-step explanation:

∡RST

∡S

∡TSR

∡4

this appears to be an obtuse angle

5 0
3 years ago
PLS ANSWER ASAP 30 POINTS!!! CHECK PHOTO! WILL MARK BRAINLIEST TO WHO ANSWERS
Sveta_85 [38]

I'll do Problem 8 to get you started

a = 4 and c = 7 are the two given sides

Use these values in the pythagorean theorem to find side b

a^2 + b^2 = c^2\\\\4^2 + b^2 = 7^2\\\\16 + b^2 = 49\\\\b^2 = 49 - 16\\\\b^2 = 33\\\\b = \sqrt{33}\\\\

With respect to reference angle A, we have:

  • opposite side = a = 4
  • adjacent side = b = \sqrt{33}
  • hypotenuse = c = 7

Now let's compute the 6 trig ratios for the angle A.

We'll start with the sine ratio which is opposite over hypotenuse.

\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(A) = \frac{a}{c}\\\\\sin(A) = \frac{4}{7}\\\\

Then cosine which is adjacent over hypotenuse

\cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(A) = \frac{b}{c}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\

Tangent is the ratio of opposite over adjacent

\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(A) = \frac{a}{b}\\\\\tan(A) = \frac{4}{\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{\sqrt{33}*\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{(\sqrt{33})^2}\\\\\tan(A) = \frac{4\sqrt{33}}{33}\\\\

Rationalizing the denominator may be optional, so I would ask your teacher for clarification.

So far we've taken care of 3 trig functions. The remaining 3 are reciprocals of the ones mentioned so far.

  • cosecant, abbreviated as csc, is the reciprocal of sine
  • secant, abbreviated as sec, is the reciprocal of cosine
  • cotangent, abbreviated as cot, is the reciprocal of tangent

So we'll flip the fraction of each like so:

\csc(\text{angle}) = \frac{\text{hypotenuse}}{\text{opposite}} \ \text{ ... reciprocal of sine}\\\\\csc(A) = \frac{c}{a}\\\\\csc(A) = \frac{7}{4}\\\\\sec(\text{angle}) = \frac{\text{hypotenuse}}{\text{adjacent}} \ \text{ ... reciprocal of cosine}\\\\\sec(A) = \frac{c}{b}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(\text{angle}) = \frac{\text{adjacent}}{\text{opposite}} \ \text{  ... reciprocal of tangent}\\\\\cot(A) = \frac{b}{a}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\

------------------------------------------------------

Summary:

The missing side is b = \sqrt{33}

The 6 trig functions have these results

\sin(A) = \frac{4}{7}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\\tan(A) = \frac{4}{\sqrt{33}} = \frac{4\sqrt{33}}{33}\\\\\csc(A) = \frac{7}{4}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\

Rationalizing the denominator may be optional, but I would ask your teacher to be sure.

7 0
1 year ago
Arun's family took a road trip to Niagara Falls. Arun fell asleep 69% of the way through the trip. If Arun fell asleep after the
Lesechka [4]
1,000 miles is the total length of the trip
7 0
3 years ago
The ratio of adult cat to kitten at a pet care center on Thursday was 4:3. There were 12 kittens there that day. Tuesday , 17 ad
emmainna [20.7K]

Answer:

1 adult cat

Step-by-step explanation:

<u>Thursday:</u>

The ratio of adult cat to kitten at a pet care center on Thursday was 4:3.

Number of adult cats = 4x

Number of kitten cats = 3x

There were 12 kittens, then

3x=12\\ \\x=\dfrac{12}{3}\\ \\x=4\\ \\4x=4\cdot 4=16

There were 16 adult cats

<u>Tuesday:</u>

17 adult cats were at the pet care center.

<u>Difference:</u>

17-16=1 adult cat

5 0
4 years ago
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