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3 years ago

Please help find the area of the triangle!

Mathematics

2 answers:

Ulleksa [173]3 years ago

7 0

1456 To find the area you have to multiply

weqwewe [10]3 years ago

4 0

45.5 you have to multiply 13 and 7 then divid by 2

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Kain graphs the hyperbola (y+2)^2/64 − (x+5)^2/36 = 1 . How does he proceed? Drag a value, phrase, equation, or coordinates in t

cupoosta [38]

Answer:

1st box: (-5,-2)

2nd box: up and down

3rd box: 8

4th box: +-4/3

5th box: y+2 = +-4/3 (x+ 5)

Step-by-step explanation:

Just took the k12 unit test, hope this helps!

7 0

3 years ago

Read 2 more answers

419.045 or 419.099 which one of these is greater and which is less.

cricket20 [7]

Answer:

419.099 is less than 419.045

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Missy has 4 times as many trading cards as her friends Ashe and Caleb combined. Ashe

diamong [38]

Answer:

Step-by-step explanation:

Missy has 156 cards in total. Since we know she has 4 times as many as them, we divide 156 by 4

156/4= 39

Ashe has 17 cards and we still don't know how many Caleb has. Since we know that they have 39 cards together, we need to subtract Ashe's cards to find how many Caleb has

39-17=22

Let's check our work

Caleb has 22 cards

Ashe has 17 cards

Together they have 39

Which is 4 times less than how many cards Missy has

Missy has 156 cards

We are correct!

5 0

3 years ago

Indicate in standard form the equation of the line through the given points. P(0, -4), Q(5.1)

Elan Coil [88]

keeping in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

$\bf P(\stackrel{x_1}{0}~,~\stackrel{y_1}{-4})\qquad Q(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{(-4)}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{0}}}\implies \cfrac{1+4}{5}\implies \cfrac{5}{5}\implies 1$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-4)}=\stackrel{m}{1}(x-\stackrel{x_1}{0})\implies y+4=x \\\\\\ y=x-4\implies -x+y=-4\implies x-y=4$