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vekshin1
3 years ago
15

I really need help please

Mathematics
1 answer:
Lana71 [14]3 years ago
6 0

Answer:

Step-by-step explanation:

We have two sides; the Adjacent and the Hypotnuse

Meaning we will use Cos

Cos = A/H

Cos X = 16/19

Use the inverse of Cos to find the angle

X = cos-1 (16/19)

X = 0.45499141546

X = 0.45

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Put the expression (48c)^3/4 in radical form hurry plz
Svet_ta [14]
Remember that if something is raised to a fraction exponent, the denominator of the fraction is the radical and the numerator stays a power. So it becomes:

fourth root of (48c)^3

Hope this helps
8 0
3 years ago
Running out of time. Please make sure you know how to do this. Can't miss too many more!!!!!
oee [108]

Answer:

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4 0
3 years ago
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I’ll give brainliest
kupik [55]

Answer:

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Graph the line with slope 1/4 and y-intercept -8
kherson [118]

Solution: Below! ^^

Detailed explanation:

Hii! I'm sorry, I can't graph the line for you, but I'll try to give you the best possible explanation.

First, note that the question provides us with the info that the y intercept is -8. This is a very valuable piece of information!

This means that the line crosses the y axis (since it's the y intercept) at the point (0,-8). Plot it on the co-ordinate plane.

Next, this question also provides us with the fact that the slope of the line is 1/4. This is yet another valuable piece of information!

What this tells us is: from that point (0,-8), you need to go up 1 unit, then over 4, and so forth, until you obtain a line.

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Hope I helped, best wishes & happy studies!

Please reach out to me if any queries arise.

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5 0
2 years ago
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What is the square root of -372
wel

Answer:

19.2873015 (Done by a calculator) <---- could be wrong

Step-by-step explanation:

And fun fact:

Negative numbers don't have real square roots since a square is either positive or 0. The square roots of numbers that are not perfect square are members of irrational numbers. This means that they can't be written as the quotient of two integers.

Hope it helps!

4 0
3 years ago
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