1y - 1/x = 1/60 = x*y =60 = x=60/y
3y - 2(60/y) = 6
3y^2-120=6y
3(y^2-40-2y) =0
y^2-40-2y=0
y = 7.4
3(7.4)-2x=6
22.2-2x = 6
2x = -16.2
x = -8.1
Answer:
10
Step-by-step explanation:
Means back the numbers into multiples of several small numbers
Like:; 1. We take LCM of 40
Just break into multiples of small number
40= 2×2×2×5
2. We take LCM of 50
50= 5×5×2
So LCM for 100 is 2×2×5×5
after that see the pairs in the LCM like 2×2 or 3×3 or 4×4(same numbers)
Then write the the single number in place of two multipled numbers
Like:; 2×2 is written as 2 // 3×3 is written as 3
So we can write 100 into 2×2×5×5 and then after selecting pairs (2×2)×(5×5)
write pairs in single number 2×5
And so we get 2×5=10
So we find root of 100 that is 10
Answer:
Assuming the area is made up of a square and a semicircle.
<u>Perimeter</u>
The side length of the square = 18 ft
We can see 3 full side lengths plus one side length from which we need to subtract 12 ft (see attached diagram).
⇒ perimeter of the square = (3 x 18) + (18 - 12)
= 54 + 6
= 60 ft
Circumference of a circle = 
d (where d is the diameter)
⇒ arc length of the semicircle = 1/2 circumference
= 1/2 · · 12
= 6 ft
Total perimeter = 60 + 6 = 78.8 ft (nearest tenth)
<u>Area</u>
Area of a square = s² (where s is the side length)
⇒ area of square = 18²
= 324 ft²
Diameter = 2r ⇒ r = 1/2 diameter
Area of a circle = r² (where r is the radius)
⇒ area of the semicircle = 1/2 · · 6²
= 18 ft²
Total area = 324 + 18 = 380.5 ft² (nearest tenth)
Answer:
Yes. the relation is a function
Step-by-step explanation:
Here, we want to check if the relation is a function
if a relation is a function, then every x-values (input values) will have one y-value
No two output values (y values) will have a single x value
Looking at the pairs;
It is a function
Although two x values have same y value; 2 and 3 to 8; no two y values have same x value
Hence, the ordered pairs is a function
Answer:
ghv hhjhjhkjhhhghbb
Step-by-step explanation:
m, bn,knn n m hmhjbh
