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OverLord2011 [107]
2 years ago
11

What are the domain and range of h(x) = 3jx|?

Mathematics
1 answer:
netineya [11]2 years ago
8 0

IDENTIFY THE TYPE OF produ

Step-by-step explanation:

ced in the following pictures write your answer on the space provided

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Pls, help me I don't understand! Very urgent!!!! (I have an attachment so you know what the problem looks like)
vredina [299]

1. A pair of supplementary angles: ∠IJH and ∠HJG, ∠IJH and ∠HJG

2. A pair of complementary angles: ∠JGK and ∠KGC, ∠FGE and ∠EGD

3. A pair of vertical angles: ∠AKB and ∠KJG , ∠IJH and ∠KJG

Solution:

<em>Two angles are said to be supplementary when they add up to 180°.</em>

We know that,

Sum of the adjacent angles in a straight line = 180°

∠IJK + ∠KJG = 180°

Therefore ∠IJK and ∠KJG are supplementary angles.

∠IJH + ∠HJG = 180°

Therefore ∠IJH and ∠HJG are supplementary angles.

<em>Two angles are said to be complementary when they add up to 90°.</em>

Given ∠CGD = 90°, ∠CGJ = 90°

∠JGK + ∠KGC = ∠CGJ

∠JGK + ∠KGC = 90°

Therefore ∠JGK and ∠KGC are complementary angles.

∠FGE + ∠EGD = 90°

Therefore ∠FGE and ∠EGD are complementary angles.

<em>If two lines are intersecting, then the angles opposite to vertical point are vertical angles and they are equal.</em>

∠AKB = ∠KJG (vertically opposite)

∠IJH = ∠KJG (vertically opposite)

5 0
3 years ago
Mane who be shaking dice?
skelet666 [1.2K]

Not me

Step-by-step explanation:

5 0
3 years ago
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Help me which one is a linear fUnction
horsena [70]

Answer:

b

Step-by-step explanation:

4 0
3 years ago
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Prove that the conjecture is false by providing a counter example.
Bas_tet [7]

Answer:

Any negative number would be a counterexample.

Step-by-step explanation:

Since negative numbers get smaller as you multiply them by a larger number, this would prove this conjecture false.

6 0
3 years ago
Take the horse to overtake the
S_A_V [24]

Answer:

  • 120 km/h

Step-by-step explanation:

  • Speed in one direction = 40 km/h
  • Speed on return = x
  • Average speed = 60 km/h

Let the distance be d

<u>Average speed </u>

  • 2d/(d/40 + d/x) = 60
  • d/40 + d/x = 2d/60
  • 1/40 + 1/x = 1/30
  • 1/x = 1/30 - 1/40
  • 1/x = (4-3)/120
  • 1/x = 1/120
  • x = 120 km/h

6 0
3 years ago
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