First distribute 4 into the corresponding parenthesis.
4x+12
Then distribute 2 into the other corresponding parentheses.
4x+18
So together you get 4x+12=4x+18
No we want to get all our variables on one side and our numbers on the other side.
We can do this by combining like terms/
First subtract 12 from both sides
4x=4x+30
Then subtract 4x from both sides
0=30
The equation is false
You don't list the "sums listed below" but I can still help you.
There are 6 ways to get a sum of 7 using a pair of dice:
1+6
6+1 You might be asking why 2+5 isn't the same as 5+2
2+5 Imagine the dice are different colors. Is a red 2 and green 5 the
5+2 same as a green 2 and red 5? (No, it's not)
3+4
4+3
You need two numbers that also provide 6 ways to win. One pair that would work is 11 and 9 There are two ways to make 11 (5+6) and (6+5) and there are four ways to make 9 (3+6), (6+3) (4+5) and (5+4) - that's a total of six ways. So to balance your friend's 7 - you could go for sums of 11's and 9's. Check the choices you were given and find the numbers (it could be three numbers like 2,3, and 12) that give you 6 ways to win.
Here are the numbers and their ways
Sum of the dice Ways to get it
2 1
3 2
4 3
5 4
6 5
7 6
8 5
9 4
10 3
11 2
12 1
Answer:
Its 2
Step-by-step explanation:
Answer:
5/4
Step-by-step explanation:
5/6+5/12
or, {(5×2)+5}/12
or, 15/12 = 5/4
I’m pretty sure its b
Don’t give me brain- whatever it is it’s most likely wrong
