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Artemon [7]
3 years ago
5

From a standard deck of cards, how many 5 card hands contain 1 ace?

Mathematics
1 answer:
saveliy_v [14]3 years ago
4 0

Answer:

525

Step-by-step explanation:

If you want exactly one ace, then your answer is correct. (525) is the number of 5-card hands in the deck, and you have 4 choices for which ace to include (hence, (41)), and 48 choose 4 choices for the other 4 cards (hence, (484)).

hope this helps!

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babymother [125]

Answer:

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C. (2i)⁴ = a. 16

D. (2i)(8i) = c. -16

Step-by-step explanation:

A. Multiply 2i by 8 to get 16i, which corresponds to d.

B. The exponent is 3 more than a mulitple of 4 in 16i³, so the answer is negative. -16i corresponds to b.

C. (2i)⁴ has an exponent that is a multiple of 4, so the i isn't needed. 16 corresponds to a.

D. (2i)(8i) simplifies to 2(8) * i². The exponent is 2 more than a multiple of 4, so the answer is negative, without an i. -16 corresponds to c.

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Need help, please what is the Domain<br> Range<br> Thanks
s2008m [1.1K]

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