Answer:
use the distance formula,
by using it, prove the adjacent sides of the quadrilateral DEFG
hence, DEFG would be a rhombus
Answer:
tan(θ) = 0, 0.577, -0.577
Step-by-step explanation:
3tan³(θ) - tan(θ) = 0
tan(θ)(3tan²(θ) - 1) = 0
tan(θ) = 0
tan²(θ) = ⅓ tan(θ) = +/- sqrt(⅓)
tan(θ) = 0, sqrt(⅓), -sqrt(⅓)
tan(θ) = 0, 0.577, -0.577
To find θ values, domain is required
Answer:
I'm confused you did not provide the graph that is referenced on this question...
Answer:
40 nickels
Step-by-step explanation:
1 2/5 to 2 1/3 = 7/5 : 7/3
= 21/15 : 35/15
21/15 = 24
35/15 = x
(35/15 * 24) / 21/15
∴ 56 ÷ 21/15
= 40 nickels
