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2 years ago

* Solve for x. (4 Points) (4x + 10% (3x - 5)º

Mathematics

2 answers:

slamgirl [31]2 years ago

8 0

I wish I new but look just try or best

liq [111]2 years ago

5 0

25. Brainliest?? Have a nice day tho

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Find the ratio of 700m to 2 km

Anika [276]

Answer:

7 : 20

Step-by-step explanation:

2km = 2000m

Then the ratio of 700m to 2 km is :

700 / 2000

Then the ratio in simplest form is :

7 / 20

7 0

2 years ago

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Write an expression for the calculation subtract 12 doubled from 132

prisoha [69]

Step-by-step explanation:

Doubled of 132 which means 2 times 132 =

Subtract 12 doubled from 132

While write the expression whatever the expression after the word from that we have to write first

So Doubled of 132 - 12

- 12 -----> This is the final expression

If we simplify the above expression we will get

264 - 12

= 252

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2 years ago

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Please help me with this question.

oksano4ka [1.4K]

Answer:

the centroid i believe...

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3 years ago

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Answer????? with steps

Alchen [17]

6000 x 10% x 5

=600x5
=3000

4 0

2 years ago

a circle is inscribed in a square. the circumference of the circle is increading at a constant rate of 6 inches per second. As t

Burka [1]

Answer:

The rate at which Perimeter of the square is increasing is $\frac{24}{\pi} \ in/secs$ .

Step-by-step explanation:

Given:

Circumference of the circle = $2\pi r$

Rate of change of in circumference = 6 in/secs

We need to find the rate at which the perimeter of the square is increasing

Solution:

Now we know that;

$\frac{d(2\pi r)}{dt} =6\\\\2\pi\frac{dr}{dt}=6\\\\\frac{dr}{dt}=\frac{6}{2\pi}\\\\\frac{dr}{dt}=\frac{3}{\pi}$

Now we know that;

side of the square= diameter of the circle

side of the square = $2r$

Now Perimeter of the square is given by 4 times length of the side.

$P=4\times 2r =8r$

Now we need to find the rate at which Perimeter is increasing so we will find the derivative of perimeter.

$\frac{dP}{dt}= \frac{d(8r)}{dt}\\\\\frac{dP}{dt}= 8\times\frac{dr}{dt}$

But $\frac{dr}{dt} =\frac{3}{\pi}$

So we get;

$\frac{dP}{dt}= 8\times\frac{3}{\pi}\\\\\frac{dP}{dt}= \frac{24}{\pi}\ in/sec$

Hence The rate at which Perimeter of the square is increasing is $\frac{24}{\pi} \ in/secs$ .

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3 years ago