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2 years ago

(14 + 3/2b)-(1+8/2b)

Mathematics

2 answers:

Ray Of Light [21]2 years ago

7 0

3b/2 +9

hopefully that helps

Veronika [31]2 years ago

6 0

Answer:

13-5/2b

Step-by-step explanation:

(14+3/2b)-(1+4b)

14+3/2b-1+4b

13-5/2b

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If two different people are randomly selected from the 864 subjects, find the probability that they are both heavy smokers. Roun

AlekseyPX

Answer:

P = 0.008908

Step-by-step explanation:

The complete question is:

The table below describes the smoking habits of a group of asthma sufferers

Nonsmokers Light Smoker Heavy smoker Total

Men 303 35 37 375

Women 413 31 45 489

Total 716 66 82 864

If two different people are randomly selected from the 864 subjects, find the probability that they are both heavy smokers.

The number of ways in which we can select x subjects from a group of n subject is given by the combination and it is calculated as:

$nCx=\frac{n!}{x!(n-x)!}$

Now, there are 82C2 ways to select subjects that are both heavy smokers. Because we are going to select 2 subjects from a group of 82 heavy smokers. So, it is calculated as:

$82C2=\frac{82!}{2!(82-2)!}=3321$

At the same way, there are 864C2 ways to select 2 different people from the 864 subjects. It is equal to:

$864C2=\frac{864!}{2!(864-2)!}=372816$

Then, the probability P that two different people from the 864 subjects are both heavy smokers is:

$P=\frac{82C2}{864C2}=\frac{3321}{372816}=0.008908$

4 0

3 years ago

Solve this equation. -4(p+2)+8=2(p-1)-7p+15

ratelena [41]

Hey there!

First we have to $distribute$ !

$-4 (p +2) = +8 = 2(p - 1) -7p + 15 \\ -4(p) + -4(2) + 8 = 2(p) +-2 + -7p + 15$

Now, we have to $combine$ our like terms

$-4p + (-8 + 8) = 2p + (-7p) + (-2) + 15 
$

Once we solve all the $like-terms$ we get

$-4p = 5p +13$

Now, we have to $add$ $5p$ to each of your sides

$-4p + 5p \\ = -5p + 13 + 5p$

Solve that part of the equation

$p= 13$

Good luck on your assignment and enjoy your assignment

~ $LoveYourselfFirst:)$

7 0

3 years ago

Which point is in the solution set of the given system of inequalities 3x+y>-3,x+2y<4

Dima020 [189]

Step 1. Solve both inequalities for $y$ :
$3x+y\ \textgreater \ -3$
$y\ \textgreater \ -3x-3$

$x+2y\ \textless \ 4$
$2y\ \textless \ -x+4$
$y\ \textless \ - \frac{1}{2} x+2$

Step 2. To check a point in the solution of the given system of inequalities, look for the intercepts of the lines $-3x-3$ and $- \frac{1}{2} x+2$ :

$y=-3x-3$ (1)
$y=- \frac{1}{2} x+2$ (2)

Replace (1) in (2):
$-3x-3=- \frac{1}{2} x+2$
Solve for $x$ :
$\frac{5}{2} x=-5$
$x=-2$ (3)

Replace (3) in (1):
$y=-3x-3$
$y=-3(-2)-3$
$y=6-3$
$y=3$

We can conclude that the point (-2,3) is in the solution of the system if <span>inequalities</span>; also any point inside the dark shaded area of the graph of the system of inequalities is also a solution of the system.