The slope of the line that passes through points -2,3 and 10,3 is

Mathematics

2 answers:

Ray Of Light [21]2 years ago

3 0

Answer:

i gave you the slope and if its a function

Step-by-step explanation:

it a function

Slope (m) = ΔYΔX= 0

θ = arctan( ΔY )ΔX= 0°

ΔX = 10 – -2 = 12

ΔY = 3 – 3 = 0

Distance (d) = √ΔX2 + ΔY2 = √144 = 12

Equation of the line:

y = 0x + 3

When x=0, y = 3

katen-ka-za [31]2 years ago

3 0

Answer:

m = 1/7

Step-by-step explanation:

Start with the slope formula (m= y2 - y1 / x2 - x1)

Plug y2 with 5, y1 with 6, x2 with 3, and x1 with 10

Subtract 6 from 5 to get 1, and subtract 10 from 3 to get -7

Simplify the answer to 1/7

So the slope is m= 1/7

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If sec= 5/3 and the terminal point determined by is in quadrant 4, then

OLga [1]

$\bf sec(\theta)=\cfrac{1}{cos(\theta)}\\\\
-----------------------------\\\\
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\\\\\\
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so... notice the picture below, the angle in the fourth quadrant
now... notice, the cosine is just the distance the angle makes with the x-axis
so... using the pythagorean theorem, get the opposite side, from that triangle, keeping in mind that, "y" is negative in the 4th quadrant

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