Answer:
Below in bold.
Step-by-step explanation:
1) as ABCD is a rhombuc AC bisects < BAD and < BCD .
Therefore < CAD = 1/2 * 104 = 52 degrees.
2) < ACG = < ADC + < CAD ( External angle of triangle theorem)
Therfore < ACG = 76 + 52 = 128 degrees.
The distance between the boats after 1 minute would be 130 ft.
Given that a lake is 200ft wide, and two boats start to move towards one another from opposite shores, and in one minute, the first boat goes 40 ft and the second one goes 30 ft, to determine what would be the distance between the boats after 1 minute the following calculation must be performed:
- Total width - boat distance 1 - boat distance 2 = Distance after 1 minute
- 200 - 40 - 30 = X
- 130 = X
Therefore, the distance between the boats after 1 minute would be 130 ft.
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The photo has the answer you need
Answer:
6
Step-by-step explanation:
JM is 6 riiite
and JMN should be an equilateral triangle so
If we have a circle with a radius of 3 we need to find the diameter of the circle. Remember radius is half of the diameter. So, the diameter is 6 units.
Use the circumference formula: C=3.14D
C=3.14(6)
C=18.84 units