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Anna007 [38]
3 years ago
11

I need help ASAP?!!!!!!

Mathematics
1 answer:
Elodia [21]3 years ago
3 0

Answer:

x = 2

Step-by-step explanation:

5x - 6 = 4

add 6 to each side

5x = 10

divide each side by 5

x = 2

You might be interested in
Find the percentage area of moss in a lawn if 3 out of 24 squares contained moss
Luba_88 [7]

3 out of 24 = \frac{3}{24} = \frac{1}{8} = 0.125   = 12.5%

7 0
3 years ago
Read 2 more answers
PLEASE HELP ME GUYS OR I WONT PASS <br>this calculus!!!!​
KonstantinChe [14]

Answer:

b.  \displaystyle \frac{1}{2}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Functions
  • Function Notation
  • Exponential Rule [Rewrite]:                                                                              \displaystyle b^{-m} = \frac{1}{b^m}
  • Exponential Rule [Root Rewrite]:                                                                     \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}<u> </u>

<u>Calculus</u>

Derivatives

Derivative Notation

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                       \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle H(x) = \sqrt[3]{F(x)}<em />

<em />

<u>Step 2: Differentiate</u>

  1. Rewrite function [Exponential Rule - Root Rewrite]:                                      \displaystyle H(x) = [F(x)]^\bigg{\frac{1}{3}}
  2. Chain Rule:                                                                                                        \displaystyle H'(x) = \frac{d}{dx} \bigg[ [F(x)]^\bigg{\frac{1}{3}} \bigg] \cdot \frac{d}{dx}[F(x)]
  3. Basic Power Rule:                                                                                             \displaystyle H'(x) = \frac{1}{3}[F(x)]^\bigg{\frac{1}{3} - 1} \cdot F'(x)
  4. Simplify:                                                                                                             \displaystyle H'(x) = \frac{F'(x)}{3}[F(x)]^\bigg{\frac{-2}{3}}
  5. Rewrite [Exponential Rule - Rewrite]:                                                              \displaystyle H'(x) = \frac{F'(x)}{3[F(x)]^\bigg{\frac{2}{3}}}

<u>Step 3: Evaluate</u>

  1. Substitute in <em>x</em> [Derivative]:                                                                              \displaystyle H'(5) = \frac{F'(5)}{3[F(5)]^\bigg{\frac{2}{3}}}
  2. Substitute in function values:                                                                          \displaystyle H'(5) = \frac{6}{3(8)^\bigg{\frac{2}{3}}}
  3. Exponents:                                                                                                        \displaystyle H'(5) = \frac{6}{3(4)}
  4. Multiply:                                                                                                             \displaystyle H'(5) = \frac{6}{12}
  5. Simplify:                                                                                                             \displaystyle H'(5) = \frac{1}{2}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

5 0
3 years ago
This week, Sarah spent a total of 120 minutes studying. This total was 20 more
MrMuchimi

Answer:

She spent 25 minutes studying last week

Step-by-step explanation:

L = last week

120 = 4L + 20

Subtract 20 from either side

100 = 4L

Divde either side by 4

25 = L

4 0
3 years ago
You have a credit card with a balance of $754.43 at a 13.6% APR. You have $300.00 available each month to save or pay down your
pochemuha
 <span>B(n) = A(1 + i)^n - (P/i)[(1 + i)^n - 1] 

where B is the balance after n payments are made, i is the monthly interest rate, P is the monthly payment and A is the initial amount of loan. 

We require B(n) = 0...i.e. balance of 0 after n months. 

so, 0 = A(1 + i)^n - (P/i)[(1 + i)^n - 1] 

Then, with some algebraic juggling we get: 

n = -[log(1 - (Ai/P)]/log(1 + i) 

Now, payment is at the beginning of the month, so A = $754.43 - $150 => $604.43 

Also, i = (13.6/100)/12 => 0.136/12 per month 

i.e. n = -[log(1 - (604.43)(0.136/12)/150)]/log(1 + 0.136/12) 

so, n = 4.15 months...i.e. 4 payments + remainder 

b) Now we have A = $754.43 - $300 = $454.43 so, 

n = -[log(1 - (454.43)(0.136/12)/300)]/log(1 + 0.136/12) 

so, n = 1.54 months...i.e. 1 payment + remainder 
</span>
8 0
3 years ago
WHat is the value of 599 x (400+37) QUICKKKKKK!!<br><br> 239,637<br> 261,763<br> 432,599<br> 599,437
leva [86]

Answer:

b: 261,763

Step-by-step explanation:

do the parenthesis then mutiply the 2 #s

8 0
3 years ago
Read 2 more answers
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