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andrew-mc [135]
3 years ago
9

Answer please thank you

Mathematics
2 answers:
sergiy2304 [10]3 years ago
8 0
I am not sure maybe it is 6
lana [24]3 years ago
5 0
-6 greater than or equal to x
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Write each repeating decimal using bar
SVETLANKA909090 [29]

Answer:

*The bar is supposed to go on top of the number, but I will put it at the bottom because I don't know how to do it at the top*

a) 0.<u>5</u>

b) 0.<u>13456</u>

Step-by-step explanation:

a) The 5 is repeating so you put the bar on top of the 5

b) The number 13456 is repeated so you put the bar on top of the 13456

6 0
3 years ago
Help me on this question..........
aleksandrvk [35]
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Use the exponential decay​ model, Upper A equals Upper A 0 e Superscript kt​, to solve the following. The​ half-life of a certai
Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

A=A_0 e^{kt}

Where,

A_0 = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = \frac{A_0}{2},

i.e.

\frac{A_0}{2}=A_0 e^{19k}

\frac{1}{2} = e^{19k}

0.5 = e^{19k}

Taking ln both sides,

\ln(0.5) = \ln(e^{19k})

\ln(0.5) = 19k

\implies k = \frac{\ln(0.5)}{19}\approx -0.03648

Now, if the substance to decay to 78​% of its original​ amount,

Then A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0

0.78 A_0=A_0 e^{-0.03648t}

0.78 = e^{-0.03648t}

Again taking ln both sides,

\ln(0.78) = -0.03648t

-0.24846=-0.03648t

\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7

Hence, approximately the substance would be 78% of its initial value after 7 years.

5 0
3 years ago
Round each number to the nearest ten 24. 311. 107
astraxan [27]

Answer:

24-20   311-310     107-110

Step-by-step explanation:

3 0
3 years ago
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A carpenter has a board that is 10 feet long. He wants to make 6 table legs that are all the same length. What is the longest ea
Zielflug [23.3K]
1 board that is 10 feet long and make that into 6 table legs. Take the amount we have over the amount we want, so 10 over 6 which is 1.6666667 feet which is the longest each leg can be for a 10-foot board.
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3 years ago
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