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3 years ago

14

Simplify 7x-2xy + 9xy - 2x + 5 Please help

1 answer:

viktelen [127]3 years ago

5 0

Answer:

7x-2xy+9xy-2x+5

7x-2x-2xy+9xy+5

5x+7xy+5

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Factor ab + bc + b2 + ac.<br><br> (a + b)(b + c)<br> (a + c)(b + c)<br> b(a + b)(b + c)

Aleks04 [339]

Answer:

<u>It</u><u> </u><u>is</u><u> </u><u>(</u><u>a</u><u> </u><u>+</u><u> </u><u>b</u><u>)</u><u>(</u><u>b</u><u> </u><u>+</u><u> </u><u>c</u><u>)</u>

Step-by-step explanation:

$ab + bc + {b}^{2} + ac$

arrange the function:

$= (ab + ac) + ( {b}^{2} + bc)$

factorise out common terms [ a and b ]:

$= a(b + c) + b(b + c)$

form a bracket of factors:

$= (a + b)(b + c)$

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3 years ago

Jessica is deciding on her schedule for next semester. She must take each of the following classes: English 101, Spanish 102, Bi

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3 years ago

Which exponential function goes through the points (1, 16) and (4, 128)?

djyliett [7]

Answer:

Here is the complete question (attachment).

The function which represent the given points are $f(x)=8(2)^{x}$

Step-by-step explanation:

We know that a general exponential function is like, $y=a(b)^{x}$

We can find the answer by hit and trial method by plugging the values of $(x,y)$ coordinates.

Here we are going to solve this with the above general formula.

So as the points are $(1,16)$ then for $x=1,\ y=16$

Can be arranged in terms of the general equation.

$ab^1=16$ ...equation(1) and $ab^4=128$ ...equation(2)

$a\times b=16, then\ a=\frac{16}{a}$

Plugging the values in equation 2.

We have

$\frac{16}{b} b^4=128,16\times b^3=128,b=\sqrt[3]{\frac{128}{16}} =\sqrt[3]{8}=2$

Plugging $b=2$ in equation 1.

We have $a=\frac{16}{b} =\frac{16}{2} =8$

Comparing with the general equation of exponential $a=8$ and $b=2$

So the function which depicts the above points = $y=8(2)^x$

From theoption we have B as the correct answer.

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4 years ago

Hey can anyone help me ?

Komok [63]

Answer:

6

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The area of a triangle is 225 in^2. If the width is 18 inches, find the height of the triangle

sergiy2304 [10]

$\textit{area of a triangle}=\cfrac{1}{2}\cdot b\cdot h\qquad 
\begin{cases}
b=\textit{base of triangle,}\\
\qquad \textit{may also be its width}\\
h=\textit{height of triangle}
\end{cases}
\\ \quad \\
b=width=18\qquad area=225
\\ \quad \\
225=\cfrac{1}{2}\cdot 18\cdot h\impliedby \textit{solve for "h"}$

6 0

3 years ago